Question

employeeStructureSchema.js

var employeeStructureSchema = new Schema({
    name: String
});
module.exports = mongoose.model('employeeSturctureModel', employeeStructureSchema);

companySchema.js

var employeeStructureSchema = require('./employeeStructureSchema.js').schema;

var companySchema = new Schema({
    companyName: String,
    phone: String,
    email: { type: String, lowercase: true },
    companyAddress: String,
    settings: {
        "employees": [employeeSchema],
    },
});
module.exports = mongoose.model('companies', companySchema);

我的目标是删除一些名字以＆＃34;虚拟用户＆＃34;来自settings.employees

我试过以下查询。这是工作。你可以建议吗

db.companies.update({"_id":objectId},{$pull:{"settings.employees":{ $elemMatch: {name: /^dummy user/}}}});

我的单个文件是这样的：

{ 
    "_id" : ObjectId("563b35d1f07cc9d80a26436c"), 
    "settings" : {
        "employees" : [
            {
                "_id" : ObjectId("583d28253722e240103e0108"), 
                "name" : "dummy user"
            }, 
            {
                "_id" : ObjectId("583d282e3722e240103e0109"), 
                "name" : "dummy user1"
            }, 
            {
                "_id" : ObjectId("583d28403722e240103e010b"), 
                "name" : "dummy user2"
            }
        ]
    }
}

Answer 1

假设您的员工姓名是一种列表。您可以尝试这样的查询：

db.companies.update({},{$pull: {settings.employees.name: { $regex: '^dummy user'} }});

由于您的架构受到限制，因此该查询应该可以正常工作

  db.companies.update({},{
   '$pull': {
      'settings.employees': {
          'name':{ $regex: '^dummy user'}
      }
    }
  });

来自条件mongodb的子模式$ pull

1 个答案: