Question

我试图找出如何在我的用户模型中编写方法，该方法在一行中显示用户的全名和用户所在组织的标题。

在我的用户模型中，我有一个名为full_name的方法，它可以将名字和姓氏属性一起添加。那部分有效。

现在，我尝试编写名为＆＃39; formal_title＆＃39;的方法，将用户的全名添加到organisation.title。

我有用户和组织的模型。协会是：

用户

belongs_to :organisation

组织

has_many :users

我的组织表有一个名为：title。

的属性

我在用户模型中编写方法的尝试是：

def full_name
    if first_name.present?
      [*first_name.capitalize, last_name.capitalize].join(" ")
    else
      test_full_name
    end
  end

  def organisation_title
    Organisation.title.where(organisation.id == self.organisation_id).titleize
  end

  def formal_title
        [*self.full_name, self.organisation_title].join(",")
    end

当我尝试这个时，我在控制台中收到错误消息：

NoMethodError: undefined method `formal_title' for #<User:0x007fea3495fe90>

此错误消息对我没有意义，因为我在其上测试此用户的用户具有要测试的名字，姓氏和组织ID。用户表中的organisation_id引用了一个具有标题的组织，因此我不知道为什么这个方法的任何部分可能会丢失，但也不知道控制台对该方法的了解程度。< / p>

任何人都可以看到我做错了吗？

整个用户模型具有：

class User < ApplicationRecord
  rolify strict: true # strict means you get true only on a role that you manually add
  attr_accessor :current_role


  # Include default devise modules. Others available are:
  # :confirmable, :lockable, :timeoutable and :omniauthable
  devise :database_authenticatable, :registerable,
         :recoverable, :rememberable, :trackable, :validatable,
                 :confirmable, :lockable,
         :omniauthable, :omniauth_providers => [ :linkedin, :twitter, :orcid ]


  # --------------- associations

  belongs_to :organisation, optional: true

  has_one :device
  has_many :identities, dependent: :destroy
  has_one :profile, dependent: :destroy
  has_one :setting, dependent: :destroy
  has_one :org_request, dependent: :destroy
  has_many :proposals, dependent: :destroy

  # Conversations
  has_many :authored_conversations, class_name: 'Conversation', foreign_key: 'author_id'
  has_many :received_conversations, class_name: 'Conversation', foreign_key: 'received_id'
  has_many :personal_messages, dependent: :destroy
  # End Conversations

  # teams
  has_many :teams, foreign_key: "team_mate_id"
  has_many :team_projects, through: :teams, source: :proposal
  has_many :received_invitations, :class_name => "TeamInvitation", :foreign_key => 'recipient_id'
  has_many :sent_invitations, :class_name => "TeamInvitation", :foreign_key => 'sender_id'




  # --------------- scopes

  # --------------- validations

  validates :first_name, presence:  { message: 'First name cannot be blank.' }
  validates :last_name, presence:   { message: 'Last name cannot be blank.'  }
  validates :email,     format:     { with: EMAIL_REGEX }
  validates :email,     uniqueness: { message: 'This email is already associated with an account. Try logging in.'}

   # validates_format_of :first_name, with: /a-zA-Z/
   # validates_format_of :last_name, with: /a-zA-Z/
   # validates_length_of :password, within: 8..128


  # --------------- class methods

  def full_name
    if first_name.present?
      [*first_name.capitalize, last_name.capitalize].join(" ")
    else
      "test_full_name"
    end
  end

  def organisation_title
  # you don't need to do `Organisation.where...` here because you have defined the `belongs_to` association for `:organisation`. So, it will directly give you the `Organisation` object.
    organisation.title.titleize
  end

  def formal_title
        [*self.full_name, self.organisation_title].join(",")
    end
  # --------------- instance methods
  def online?
    true
    # false
    # !Redis.new.get("user_#{self.id}_online").nil?
  end



end

Answer 1

请尝试更改此代码，并告诉我它的内容：

def full_name
  if first_name.present?
    [first_name.capitalize, last_name.capitalize].join(" ")
  else
    test_full_name  # will work if test_full_name is defined inside this class
  end
end

def organisation_title
  # you don't need to do `Organisation.where...` here because you have defined the `belongs_to` association for `:organisation`. So, it will directly give you the `Organisation` object.
  organisation.title.titleize
end

def formal_title
  [self.full_name, self.organisation_title].join(",")
end

Answer 2

我每次都保存更改。然后我在控制台中reload!。

还不够。您应该重新启动控制台或重新查询用户。

u = User.find(u.id)

reload!不会影响已加载的对象，因此您拥有的用户不会看到新方法。

Rails - 如何编写使用不同模型的属性的方法

2 个答案: