Question

我托管了WCF服务，并且我试图在iPhone应用程序中将其用作JSON POST请求。我打算稍后使用JSON序列化程序，但这就是我对请求的要求：

    NSString *jsonRequest = @"{\"username\":\"user\",\"password\":\"letmein\"}";
    NSLog(@"Request: %@", jsonRequest);

    NSURL *url = [NSURL URLWithString:@"https://mydomain.com/Method/"];

    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url];
    NSData *requestData = [NSData dataWithBytes:[jsonRequest UTF8String] length:[jsonRequest length]];

    [request setHTTPMethod:@"POST"];
    [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
    [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
    [request setValue:[NSString stringWithFormat:@"%d", [requestData length]] forHTTPHeaderField:@"Content-Length"];
    [request setHTTPBody: requestData];

    [NSURLConnection connectionWithRequest:[request autorelease] delegate:self];

在收到的数据中，我只是将其打印到控制台：

- (void) connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
{
    NSMutableData *d = [[NSMutableData data] retain];
    [d appendData:data];

    NSString *a = [[NSString alloc] initWithData:d encoding:NSASCIIStringEncoding];

    NSLog(@"Data: %@", a);
}

在这个回复中，我得到了这样的信息：

Data: ï»¿<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
  <head>
    <title>Request Error</title>
    <style>
        <!-- I've took this out as there's lots of it and it's not relevant! -->
    </style>
  </head>
  <body>
    <div id="content">
      <p class="heading1">Request Error</p>
      <p xmlns="">The server encountered an error processing the request. Please see the <a rel="help-page" href="https://mydomain.com/Method/help">service help page</a> for constructing valid requests to the service.</p>
    </div>
  </body>
</html>

有谁知道为什么会发生这种情况以及我哪里出错？

我已经阅读了有关使用ASIHTTPPost的内容，但我无法让该演示在iOS4中运行：（

由于

编辑：

我刚刚用CharlesProxy来嗅出我从iPhone（模拟器）打电话时发生的事情，这就是它给我的： alt text

~~我注意到的唯一奇怪的是它说“未为此主机启用SSL代理：在代理设置，SSL位置启用”。有谁知道这意味着什么？~~（这也发生在我工作的Windows客户端）。

我刚刚在我的Windows客户端上运行它，唯一不同的是加密的请求和响应文本。我是否遗漏了某些内容以便使用安全的HTTP连接来执行此操作？

新编辑：这适用于非HTTPS请求，例如： http://maps.googleapis.com/maps/api/geocode/json?address=UK&sensor=true。所以我想问题是让iPhone通过SSL正确发送POST？

我也在使用这些方法：

- (void) connection:(NSURLConnection *)connection didReceiveAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge
{
    if([challenge.protectionSpace.authenticationMethod isEqualToString:NSURLAuthenticationMethodServerTrust])
    {
        [challenge.sender useCredential:[NSURLCredential credentialForTrust:challenge.protectionSpace.serverTrust]
        forAuthenticationChallenge:challenge];
    }

    [challenge.sender continueWithoutCredentialForAuthenticationChallenge:challenge];
}

- (void) connection:(NSURLConnection *)connection canAuthenticateAgainstProtectionSpace:(NSURLProtectionSpace *)protectionSpace
{
    if([[protectionSpace authenticationMethod] isEqualToString:NSURLAuthenticationMethodServerTrust])
    {
        return YES;
    }
}

这让我可以做到这一点。如果我不使用它们，我会收到错误回复说：

此服务器的证书无效。您可能连接到假冒“mydomain.com”的服务器，这可能会使您的机密信息面临风险。

Answer 1

固定！

更改：

[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];

为：

[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];

您还需要以下两种方法：

- (void) connection:(NSURLConnection *)connection didReceiveAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge
{
    if([challenge.protectionSpace.authenticationMethod isEqualToString:NSURLAuthenticationMethodServerTrust])
    {
        [challenge.sender useCredential:[NSURLCredential credentialForTrust:challenge.protectionSpace.serverTrust]
        forAuthenticationChallenge:challenge];
    }

    [challenge.sender continueWithoutCredentialForAuthenticationChallenge:challenge];
}

- (void) connection:(NSURLConnection *)connection canAuthenticateAgainstProtectionSpace:(NSURLProtectionSpace *)protectionSpace
{
    if([[protectionSpace authenticationMethod] isEqualToString:NSURLAuthenticationMethodServerTrust])
    {
        return YES;
    }
}

Answer 2

我根本不了解Objective C，但尝试将Accept标头设置为application/json而不是application/jsonrequest。

Answer 3

变化

NSData *requestData = [NSData dataWithBytes:[jsonRequest UTF8String] length:[jsonRequest length]];

到

NSData *requestData = [jsonRequest dataUsingEncoding:NSUTF8StringEncoding];

Answer 4

dic是带有对象和键的NSMutable Dictionary。 baseUrl是您的服务器webservice url。

 NSData *jsonData = [NSJSONSerialization dataWithJSONObject:dic
                                                       options:NSJSONWritingPrettyPrinted error:nil];
    NSString *jsonString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding];
   NSString *encodedString = [jsonString base64EncodedString];

    NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"%@wsName",baseUrl]];
    NSMutableURLRequest *theRequest = [NSMutableURLRequest requestWithURL:url];
    [theRequest addValue: @"text/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
    [theRequest setHTTPMethod:@"POST"];
    [theRequest setValue:encodedString forHTTPHeaderField:@"Data"];

iPhone上的JSON POST请求（使用HTTPS）

4 个答案: