Question

我有一个XML：

<?xml version="1.0" encoding="UTF-8"?>
<COLLECTION>
<Added>
<part>
<weight>5kg</weight>

</part>
<part>
<weight></weight>
</part>
<part>
<weight>2kg</weight>
</part>
</Added>
<Update>
<part>
<weight></weight>
</part>
<part>
<weight>3kg</weight>
</part>
<part>
<weight>2kg</weight>
</part>
</Update>
</COLLECTION>

我想在其上应用XSL，以便<weight>标记需要转换为Weight并考虑唯一的数字。这样我想添加一些额外的标记，这在输入XML中不存在。 <unitWeights>如果<weight>的价值仅为止，只有当它显示KG休息时才会为空。

预期产出：

<?xml version="1.0" encoding="UTF-8"?>
<COLLECTION>
<Added>
<part>
<Weight>5</Weight>
<unitWeights>KG</unitWeights>
</part>
<part>
<Weight></Weight>
<unitWeights></unitWeights>
</part>
<part>
<Weight>2</Weight>
<unitWeights>KG</unitWeights>
</part>
</Added>
<Update>
<part>
<Weight></Weight>
<unitWeights></unitWeights>
</part>
<part>
<Weight>3</Weight>
<unitWeights>KG</unitWeights>
</part>
<part>
<Weight>2</Weight>
<unitWeights>KG</unitWeights>
</part>
</Update>
</COLLECTION>

为此我申请了：

    <xsl:template match="Weight">
    <weight>
      <xsl:value-of select="translate(.,translate(., '0123456789', ''), '')"/>
    </weight>
  </xsl:template>
  <xsl:template match="WeightUnits">
    <unitWeights>KG</unitWeights>
    </xsl:template>

请帮我解决我错的地方。

Answer 1

以下是满足您要求的通用解决方案。

对于只有'权重'的节点，您需要处理或应用模板。
```
<xsl:template match="weight">
```
然后您需要应用此处提到的translate来仅提取字符串部分和仅提取数字部分。 XPath - extract numeric value out of string

为您演示：http://xsltransform.net/ejivdHb/23

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns1="http://locomotive/bypass/docx" >
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<!-- identity transform -->
<xsl:template match="node()">
    <xsl:copy>
        <xsl:apply-templates select="node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="weight">

    <xsl:variable name="currentWeight" select="translate(.,translate(., '0123456789', ''), '')" />
    <xsl:variable name="currentWeightUnit" select="translate(., '0123456789', '')" />

     <xsl:if test="string-length($currentWeight) &gt; 0">
         <Weight>
            <xsl:value-of select="$currentWeight"/>
        </Weight>
        <xsl:if test="string-length($currentWeightUnit) &gt; 0">
           <unitWeights>
             <xsl:value-of select="$currentWeightUnit"/>
           </unitWeights>
        </xsl:if>
      </xsl:if>
</xsl:template>

</xsl:stylesheet>

Answer 2

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="weight">
    <Weight>
      <xsl:copy-of select="substring-before(.,'kg')"/>
    </Weight>

    <unitWeights>
      <xsl:copy-of select="substring(., string-length(.) - 1)"/>
    </unitWeights>
  </xsl:template>

  <xsl:template match="unitWeights"/>

</xsl:stylesheet>

如何执行XSL以从xml标记中删除文本

2 个答案: