Question

我正在尝试创建一个包含一些基本信息的结构数组。我的代码如下：

typedef struct {
    char firstName[30];
    char lastName[30];
    char street[35];
    char city[20];
    char state[3];
    int zip;
    char phone[15];
    int accountId;
} Customer;

int main(void) {

int i, customer_number, _zip, _accountId;
struct Customer customer_list[9];
char _firstName[30], _lastName[30], _street[35], _city[20], _state[3], _phone[15];


    for (i = 0; i < 10; i++) {
        customer_number = 0;
        printf("Enter data for customer %d: \n", customer_number);
        printf("Enter First Last Phone: ");
        scanf("%s%s%s", &_firstName, &_lastName, &_phone);

        printf("\nEnter Address (Street City State ZIP): ");
        scanf("%s%s%s%d", &_street, &_city, &_state, &_zip);

        Customer customer_list[i] = {[i].firstName = _firstName}

    }

    return 0;
}

看起来这应该有效，但我收到的错误是＆＃34;我必须有恒定的价值＆＃34;任何人都可以把我推向正确的方向吗？谢谢！

Answer 1

<span data-audio-file-url="{{ AUDIO_FILES_URL }}{{ audio_file_path }}">{{ audio_file_description }}</span>

此行必须

Customer customer_list[i] = {[i].firstName = _firstName}

编辑：作业应由strcpy(customer_list[i].firstName, _firstName);

完成

创建结构数组

1 个答案: