Question

我正在测试一个包含信息列表和卡列表的网页。因此，为了使用方法选择正确的卡，我有以下内容：

getCardByName(expectedName: string): CardActions {
    console.log("WatchActions: Getting Card of " + expectedName);
    let majorCount = 1;

    /*
     * watchPageObject.cards: ElementArrayFinder = this.tab.$$('card-watch');
     */
    let theCard = this.watchPageObject.cards.filter(function (elCard, index) {
        return elCard.getText().then(
            function (name) {
                name = name.substr(0, name.search('\nAge:'));
                console.log(majorCount++ + "-" + index + ") " + name + 
                            " = " + (name == expectedName));
                return name == expectedName;
            });
    }).first();

    return new CardActions(new CardPageObject(theCard));
}

明显的缺陷显而易见，如果有两个或更多匹配，则永远不会引用第二个匹配。如有必要，我会越过那个逻辑桥梁。

该方法正常工作，我得到了我期待的返回值。但是，该脚本似乎需要比预期更长的时间，并且控制台日志记录将其显示出来（名称是假的）：

1-0) KERGER, FEYSAL = false
2-1) JENNINGS, JEWELLAN = false
3-2) CRAVEN, LILLARD = true
4-3) HORSTMANN, GREG = false
5-4) MEUSA, FRANKLIN = false
6-5) LAURITO, RANDOLPH = false
7-6) JHANSON, LORENE = false
8-0) KERGER, FEYSAL = false
9-1) JENNINGS, JEWELLAN = false
10-2) CRAVEN, LILLARD = true
...
90-5) LAURITO, RANDOLPH = false
91-6) JHANSON, LORENE = false
92-0) KERGER, FEYSAL = false
93-1) JENNINGS, JEWELLAN = false
94-2) CRAVEN, LILLARD = true
95-3) HORSTMANN, GREG = false
96-4) MEUSA, FRANKLIN = false
97-5) LAURITO, RANDOLPH = false
98-6) JHANSON, LORENE = false

我该怎么做才能找出为什么过滤器发现有必要循环遍历7张牌的列表14次？

我希望使用公共页面提供一个通用示例，但该测试运行完美。

FWIW：这是我提出的例子（上面的代码是打字稿，下面的代码是javascript）

describe('Test and show the progression of the .filter() method', function() {

    beforeAll(function() {
        browser.get("http://www.angulartodo.com/");
    });

    afterAll(function() {
        browser.close();
    });

    it('add values to todos', function(done) {
                // Add a number of "todos".
        var todos = ["Deposit Check", "Purchase Groceries", "Pick Up Kids"];

        todos.forEach(function(todo) {
            element(by.css('.todos form > input')).sendKeys(todo).then(function() {
                element(by.css('.todos form > button')).click();
            });
        });
        done();

    });

    it('display the map progressions', function(done) {
        var listItems = element.all(by.css('.todos ul li'));
        var majorCount = 1;
        listItems.filter(function(el, index) {
            return el.element(by.css('span:nth-child(2)')).getText().then(function(text) {
                console.log(index + ") " + text);
                return text.includes("Up");
            });
        }).getText().then(function(text) {
            console.log(text);
        });
        done();
    });
});

我该怎么做才能调试.filter（）方法？

0 个答案: