Question

返回的结果不是按顺序，我需要按顺序返回结果。

尝试记录排名。

def parse(self, response):
    sourceHtml = BeautifulSoup(response.body)
    soup = sourceHtml.find("dl", {"id": "resultList"})
    for link in soup.find_all('dd'):
        print(link.get('code'))

Answer 1

如果您想在列表中打印“代码”，只需使用"list comprehension"：

def parse(self, response):
    sourceHtml = BeautifulSoup(response.body)
    soup = sourceHtml.find("dl", {"id": "resultList"})
    return [link.get('code') for link in soup.find_all('dd')]

您还可以改进查找元素的方式并使用CSS selector：

def parse(self, response):
    soup = BeautifulSoup(response.body)
    return [link.get('code') for link in soup.select('dl#resultList dd')]

provide an underlying parser explicitly：

也是一个好主意

soup = BeautifulSoup(response.body, "html.parser")
# or soup = BeautifulSoup(response.body, "html5lib")
# or soup = BeautifulSoup(response.body, "lxml")

BeautifulSoup循环未按顺序返回

1 个答案: