我的控制器功能:
"
来自URL的我的JSON响应是:
public function displayAction(Request $request)
{
$stat = $this->get("app_bundle.helper.display_helper");
$displayData = $stat->generateStat();
return new JsonResponse($displayData);
}
从这个Response我希望将值传递给javascript文件中的变量(selfie,shared),如:
{"Total":[{"date":"2016-11-28","selfies":8},{"date":"2016-11-29","selfies":5}],"Shared":[{"date":"2016-11-28","shares":5},{"date":"2016-11-29","shares":2}]}
答案 0 :(得分:1)
你可以这样试试。
首先遍历顶层对象数据,然后遍历作为数组的数据的每个属性。
var data = {"total":[{"date":"2016-11-28","selfies":0},{"date":"2016-11-29","selfies":2},{"date":"2016-11-30","selfies":0},{"date":"2016-12-01","selfies":0},{"date":"2016-12-02","selfies":0},{"date":"2016-12-03","selfies":0},{"date":"2016-12-04","selfies":0}],"shared":[{"date":"2016-11-28","shares":0},{"date":"2016-11-29","shares":0},{"date":"2016-11-30","shares":0},{"date":"2016-12-01","shares":0},{"date":"2016-12-02","shares":0},{"date":"2016-12-03","shares":0},{"date":"2016-12-04","shares":0}]}
Object.keys(data).forEach(function(k){
var val = data[k];
val.forEach(function(element) {
console.log(element.date);
console.log(element.selfies != undefined ? element.selfies : element.shares );
});
});

答案 1 :(得分:0)
在回调中使用以下内容:
$.each(data.total, function(i, o){
console.log(o.selfies);
console.log(o.date);
// or do whatever you want here
})
因为您使用jetJSON发出请求,所以发送给回调的参数data
已经是一个对象,因此您不需要解析响应。
答案 2 :(得分:0)
试试这个:
var text ='{"Total":[{"date":"2016-11-28","selfies":0},{"date":"2016-11-29","selfies":2}],"Shared":[{"date":"2016-11-28","shares":0},{"date":"2016-11-29","shares":0}]}';
var jsonObj = JSON.parse(text);
var objKeys = Object.keys(jsonObj);
for (var i in objKeys) {
var totalSharedObj = jsonObj[objKeys[i]];
if(objKeys[i] == 'Total') {
for (var j in totalSharedObj) {
document.getElementById("demo").innerHTML +=
"selfies on "+totalSharedObj[j].date+":"+totalSharedObj[j].selfies+"<br>";
}
}
if(objKeys[i] == 'Shared') {
for (var k in totalSharedObj) {
document.getElementById("demo").innerHTML +=
"shares on "+totalSharedObj[k].date+":"+totalSharedObj[k].shares+"<br>";
}
}
}
<div id="demo">
</div>
答案 3 :(得分:0)
我做了很多研究&amp;从其他用户那里获得帮助,最终可以解决我的问题。所以想到分享我的解决方案。
$.get( "Address for my JSON data", function( data ) {
var selfie =[];
$(data.Total).each(function(){
var tmp = [
this.date,
this.selfies
];
selfie.push(tmp);
});
var shared =[];
$(data.Shared).each(function(){
var tmp = [
this.date,
this.shares
];
shared.push(tmp);
});
});