这是使用spring数据模板

Question

我在elasticsearch中有一个类型，其中包含名为created的字段（日期）。我需要在这个字段上进行dateHistogram聚合。这是正确的方法吗？有人能为我提供更好的代码片段吗？

    List<Result> results = new ArrayList<>();
    NativeSearchQueryBuilder nativeSearchQueryBuilder = new NativeSearchQueryBuilder();
    RangeFilterBuilder rangeBuilderForDate = FilterBuilder.getRangeBuilderForDate(searchCriteria.getCreatedFrom(), searchCriteria.getCreatedTo(), Field.CREATED.getFieldName());

    TermFilterBuilder statusTermFilter = FilterBuilder.getTermFilter("Active", Field.STATUS.getFieldName());

    BoolFilterBuilder boolFilterBuilder = boolFilter();
    BoolFilterBuilder should = boolFilterBuilder.must(rangeBuilderForDate, statusTermFilter);
    DateHistogramBuilder dateAggs = AggregationBuilders.dateHistogram("created").interval(getInterval(searchCriteria)).field("created");

    FiltersAggregationBuilder filterAggs = AggregationBuilders.filters("dateRange").filter(should).subAggregation(dateAggs);
    NativeSearchQuery searchQuery = nativeSearchQueryBuilder.withIndices(index).withTypes(type).addAggregation(filterAggs).build();
    Aggregations aggregations = template.query(searchQuery, new ResultsExtractor<Aggregations>() {
        @Override
        public Aggregations extract(SearchResponse response) {
            return response.getAggregations();
        }
    });

    Map<String, Aggregation> asMap = aggregations.getAsMap();
    InternalFilters aggregation = (InternalFilters)asMap.get("dateRange");
    Collection<Bucket> buckets = aggregation.getBuckets();

    for(Filters.Bucket filterBuckets : buckets) {
        Aggregations subAggs = filterBuckets.getAggregations();
        InternalDateHistogram dateSubAggs = (InternalDateHistogram) subAggs.asMap().get("created");
        for(Histogram.Bucket bucket : dateSubAggs.getBuckets()) {
            Result result = new Result();
            DateHistogram.Bucket dateBucket = (DateHistogram.Bucket) bucket;
            result.setAggCriteria(dateBucket.getKey());
            result.setCount(dateBucket.getDocCount());
            results.add(result);
        }
    }
    return results;