Question

我正在用python制作一个简单的摇滚，纸张，剪刀游戏 - 并且计数器变量出现错误，我或我的计算机科学似乎都无法放置。

import random
options = ["R", "P", "S"]
userwin = 0
computerwin = 0
counter = 0

def RPS():
    counter = counter + 1
    computerchoice = random.choice(options)
    print ("It's round number", counter, "!")
    humanchoice = input ("Do you choose rock [R], paper [P] or scissors[S]?")

    if computerchoice == "R":
        if humanchoice == "R":
            print ("Rock grinds rock - it's a draw!")
        if humanchoice == "P":
            print ("Paper wraps rock - you win!")
            userwin = userwin + 1
        if humanchoice == "S":
            print ("Rock blunts scissors - you lost!")
            computerwin = computerwin + 1

    if computerchoice == "S":
        if humanchoice == "S":
            print ("Scissors strikes scissors - it's a draw!")
        if humanchoice == "R":
            print ("Rock blunts scissors - you win!")
            userwin = userwin + 1
            if humanchoice == "P":
                print ("Scissors cuts paper - you lost!")
                computerwin = computerwin + 1

    if computerchoice == "P":
        if humanchoice == "P":
            print ("Paper folds paper - it's a draw!")
        if humanchoice == "S":
            print ("Scissors cuts paper - you win!")
            userwin = userwin + 1
        if humanchoice == "S":
            print ("Paper wraps scissors - you lost!")
            computerwin = computerwin + 1

while userwin < 10 or computerwin < 10:
    RPS()

出现的错误是

counter = counter + 1
UnboundLocalError: local variable 'counter' referenced before assignment

我之前没有遇到过这个错误 - 我不确定如何修复它。有任何想法吗？谢谢！

Answer 1

您无法在函数中分配全局变量，您需要这样做：

def RPS():
    global counter

    counter = counter + 1
    computerchoice = random.choice(options)

您必须为在函数外定义的每个变量执行此操作。

计数器变量＆＃34;未分配？＆＃34;

1 个答案: