Question

我想将两个数组转换为另一种数组格式。

这是我的代码：

var array1 = [ "Kolkata", "Begumpet", "Bellary"];

var array2 = [[[20,"Kolkata1"],[10,"Kolkata2c"]],
              [[0,"Begumpet1"],[10, "Begumpet2e"]],
              [[30, "Bellary1"],[0, "Bellary2a"]]]

console.log(array2);
var resultvalue = [];
for (i = 0; i < array2.length; i++) {
    var result = "";
    var m = 0;
    for (j = 0; j < array2[i].length; j++) {
        if(m==0){
            result += "label: '" + array1[i] + "',";
            m++;
        }
        result += " '" + array2[i][j][1] + "': " + array2[i][j][0] + ", ";
    }
    resultvalue.push(result);
}
console.log(resultvalue);

它正在产生我想要的东西，除了结果是一个字符串，而我需要实际的数组。

预期的输出对象应该是这样的：

dataset = [
    {label:"Kolkata", "Kolkata1":20, "Kolkata2c":10},
    {label:"Begumpet", "Begumpet1":0, "Begumpet2e":10},
    {label:"Bellary", "Bellary1":30, "Bellary2a":0},
];

Answer 1

您可以迭代array2并为每个条目映射一个新对象。

＆＃13;

var array1 = ["Kolkata", "Begumpet", "Bellary"],
    array2 = [[[20, "Kolkata1"], [10, "Kolkata2c"]], [[0, "Begumpet1"], [10, "Begumpet2e"]], [[30, "Bellary1"], [0, "Bellary2a"]]],
    dataset = array2.map(function (a, i) {
        var o = { label: array1[i] };
        a.forEach(function (b) {
            o[b[1]] = b[0];
        });
        return o;
    });

console.log(dataset);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 2

使用内部数组上的Array.prototype.reduce和forEach获取所需数组的另一种解决方案 - 演示如下：

var array1 = [ "Kolkata", "Begumpet", "Bellary"];
var array2 = [[[20,"Kolkata1"],[10,"Kolkata2c"]],[[0,"Begumpet1"],[10, "Begumpet2e"]],[[30, "Bellary1"],[0, "Bellary2a"]]];

var result = array2.reduce(function(p,c,i){
  var elem = {label : array1[i]};
  c.forEach(e => elem[e[1]] = e[0]);
  p.push(elem);
  return p;
},[]);

console.log(result);

.as-console-wrapper{top:0;max-height:100%!important;}

Answer 3

您可以使用此ES6代码执行此操作：

＆＃13;

var array1 = [ "Kolkata", "Begumpet", "Bellary"];
var array2 = [[[20,"Kolkata1"],[10,"Kolkata2c"]],
              [[0,"Begumpet1"],[10, "Begumpet2e"]],[[30, "Bellary1"],[0, "Bellary2a"]]]

var result = array2.map( (pairs, i) => 
    Object.assign ({ label: array1[i] }, ...pairs.map ( ([v, k]) => ({ [k]: v }))));
 
console.log(result);

＆＃13;

.as-console-wrapper { max-height: 100% !important; top: 0; }

＆＃13;

Answer 4

根据JSON结构的最佳实践，您所需的输出JSON对象中存在一些更正。所以根据我认为有效的，这是正确的代码。

此外，我使用JSON.stringify（）来打印JSON对象。

我还修改了构建输出JSON对象的方式。

＆＃13;

var array1 = ["Kolkata", "Begumpet", "Bellary"];

var array2 = [
  [
    [20, "Kolkata1"],
    [10, "Kolkata2c"]
  ],
  [
    [0, "Begumpet1"],
    [10, "Begumpet2e"]
  ],
  [
    [30, "Bellary1"],
    [0, "Bellary2a"]
  ]
];

var resultvalue = [];
for (i = 0; i < array1.length; i++) {
  var result = {};
  var temp = {};
  temp.label = array1[i];
  for (j = 0; j < 2; j++) {
    temp[[array2[i][j][1]]] = array2[i][j][0];
  }
  resultvalue.push(temp);
}

document.write(JSON.stringify(resultvalue));
console.log(resultvalue);

＆＃13;

抱歉......我们理解了这个问题...我更新了这个代码。

Answer 5

要将javascript对象转换为JSON，您必须调用JSON.stringify方法。

var jsonString = JSON.stringify(array2);

数组转换提供字符串而不是数组

5 个答案: