我必须将SYSDATE日期转换为特定的日期格式。该格式必须是这样的：'2016-11-23T15:12:48Z'。我认为这是一种奇怪的日期格式，但这是我的要求。
这必须是在Web服务消息中发送的日期。
在Oracle（12c或11g）中，我有一些功能来转换这种特定格式的日期？感谢。
答案 0 :(得分：4)
这将给你评论中提到的ISO-8601：
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11-28 04:55:15.976 30265-30325/com.example.predator.labone E/log_tag: Error parsing data org.json.JSONException: Value <!DOCTYPE of type java.lang.String cannot be converted to JSONObject
如果你真的想要select to_char(systimestamp,'YYYY-MM-DD"T"hh24:mi:sstzh:tzm') isodt from dual;
而不是时区，你可以使用：
Z答案 1 :(得分：4)
从"Z" in the timestamp format you're after means "This is in UTC"开始，您应该首先确保您的sysdate以UTC格式返回。您可以使用systimestamp和sys_extract_utc()这样执行此操作：
select to_char(sys_extract_utc(systimestamp), 'yyyy-mm-dd"T"hh24:mi:ss"Z"') dt_as_utc
from dual;
DT_AS_UTC
--------------------
2016-11-28T10:33:49Z