Question

我试图用jquery将我的php代码的结果显示给ajax文件，但我不知道该怎么做。最终数组[{"UPDATE_TIME":"2016-11-28 06:51:51"}]

我想通过ajax jquery显示这个结果。

<?php
header('Access-Control-Allow-Origin: *');

include_once "dbconfig.php";

$sql = "SELECT UPDATE_TIME
FROM   information_schema.tables
WHERE  TABLE_SCHEMA = 'vizteyl7_tarining'
   AND TABLE_NAME = 'news'";

$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        $output[] = $row;
    }

    echo json_encode($output);
} else {
    echo "0 results";
}
$conn->close();
?>

 <label>Enter TimeStamp (last updated date: <span id="lastTs"></span>)</label>

    $(document).ready(function(){
              setTs();
      })

  function setTs(){

  $.ajax({
        type: "GET",
        url:"http://example.com/stshow.php",
        dataType: "json",
        success: function(data) {
            $('#lastTs').text(data[0]);

}
});
}

Answer 1

试试这个......

$('#lastTs').text(data[0].UPDATE_TIME);

将php jsonencode数组结果显示为ajax成功函数

1 个答案: