Question

例如：

console> please enter 3 digits: 1 2 3

我只知道如何使用scanf接受1位数：

scanf("%d", &space);

Answer 1

您可以使用scanf

读取多个数字

int a, b, c;
scanf("%d %d %d", &a, &b, &c);

Answer 2

你试过了吗？

scanf("%d %d %d", &num1, &num2, &num3);

如果你知道你只想要这三个，那将会很好。如果你想要一个变量号，你需要在循环中完成它，例如：

#include <stdio.h>

int main (void) {
    int i, ch, rc, val, count;

    // Loop until we get a valid number.

    rc = 0;
    while (rc != 1) {
        printf ("Enter count: "); fflush (stdout);
        rc = scanf(" %d", &count);

        // Suck up all characters to line end if bad conversion.

        if (rc != 1) while ((ch = getchar()) != '\n');
    }

    // Do once for each number.

    for (i = 1; i <= count; i++) {
        rc = 0;
        while (rc != 1) {
            printf ("\nEnter #% 2d: ", i); fflush (stdout);
            rc = scanf(" %d", &val);
            if (rc != 1) while ((ch = getchar()) != '\n');
        }
        printf ("You entered %d\n", val);
    }

    return 0;
}

运行它会给你：

Enter count: 5

Enter # 1: 10
You entered 10

Enter # 2: 20
You entered 20

Enter # 3: 30
You entered 30

Enter # 4: 40
You entered 40

Enter # 5: 99
You entered 99

如何接受3个参数作为int

2 个答案: