Question

我试图运行代码并收到错误＆＃34;点无法解析为变量＆＃34;。为什么我收到此错误，请尝试自己运行代码并分享您获得的输出。感谢。

public class ReferenceMystery1 {
    public static void main(String[] args) {
        int a = 7;
        int b = 9;
        Point p1 = new Point(2,2);
        Point p2 = new Point(2,2);
        addToXTwice(a, p1);
        System.out.println(a + " " + b + " " + p1.x + " " + p2.x);
        addToXTwice(b, p2);
        System.out.println(a + " " + b + " " + p1.x + " " + p2.x);

    }

    public static void addToXTwice(int a, Point b) {
        a = a + a;
        p1.x = a;
        System.out.println(a + " " + p1.x);
    }
}

Answer 1

导入点类

import java.awt.Point;

替换

p1.x = a;
System.out.println(a + " " + p1.x);

到

b.x = a;
System.out.println(a + " " + b.x);

完整的工作代码是

import java.awt.Point;
public class HelloWorld{

public static void main(String[] args) {
    int a = 7;
    int b = 9;
    Point p1 = new Point(2,2);
    Point p2 = new Point(2,2);
    addToXTwice(a, p1);
    System.out.println(a + " " + b + " " + p1.x + " " + p2.x);
    addToXTwice(b, p2);
    System.out.println(a + " " + b + " " + p1.x + " " + p2.x);
}

public static void addToXTwice(int a, Point b) {
    a = a + a;
    b.x = a;
    System.out.println(a + " " + b.x);
    }
}

Answer 2

＆＃34;点＆＃34;我没办法上课程。

假设它可用并且您能够编译，那么，如前面的响应所示......您无法在addToXTwice（）方法中访问p1.x，因为输入参数是＆＃39; a＆＃39 ;和＆＃39; b＆＃39;。

使用＆＃34; import java.awt.Point＆＃34;，我收到以下编译错误

javac -g ReferenceMystery1.java ReferenceMystery1.java:18：错误：找不到符号 p1.x = a; ^ 符号：变量p1 location：class ReferenceMystery1 ReferenceMystery1.java:19：错误：找不到符号 System.out.println（a +＆＃34;＆＃34; + p1.x）; ^ 符号：变量p1 location：class ReferenceMystery1 2个错误

这些与以前的评论一致：＆＃34; p1＆＃34;不能从addToXTwice（）方法中获得。

Java中此代码的输出是什么？

2 个答案: