Question

我有一个简单的基于Tomcat的Java应用程序，它起着一种防火墙的作用 - 我从“外部”接收请求，将它们重新路由到“内部”的资源，并将结果返回到“外部”。 “

这适用于GET，但我正在尝试为不同的请求添加POST功能，但我无法使其正常工作。 “内部”远程服务器受密码保护，我无法让远程服务器接受身份验证凭据（它们适用于GET，因此凭据很好。）而是，Tomcat服务器反复调用Authenticator，最后失败。这是我得到的错误：

    java.net.ProtocolException: Server redirected too many  times (20)
        at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(HttpURLConnection.java:1848)
        at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1441)
        at com.mystuff.house.server.MyServlet.doPost(MyServlet.java:191)

我确定我做的事情很愚蠢，但我看不出它在哪里。这是servlet doPost（）例程的内容：

        URL url = new URL("HTTP", "10.10.1.101", -1, "/myresource");
        URLConnection con = url.openConnection();
        HttpURLConnection http = (HttpURLConnection) con;
        http.setRequestMethod("POST");
        http.setDoOutput(true);
        String encoded = String.valueOf(Base64.getEncoder().encode((a.getUsername().concat(":").concat(a.getPassword())).getBytes()));
        http.setRequestProperty("Authorization", "Basic "+encoded);
        http.setRequestProperty("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");

        // Read the POST payload from the front end post, write to back end post
        InputStream r = request.getInputStream();
        OutputStream os = http.getOutputStream();
        int j = 0;
        while ((j = r.read()) != -1) {
            os.write((byte) j);
        }

        http.connect();

        // Try reading the result from the back end, push it back to the front end
        try {
            InputStream i = http.getInputStream();
            OutputStream o = response.getOutputStream();

            // read/write bytes until EOF
            j = 0;
            while ((j = i.read()) != -1) {
                o.write((byte) j);
            }
        } catch (Exception ex) {
            System.out.println("AIEEEE!  Error receiving page from HTTP call");
            ex.printStackTrace();
        }

Java中的HTTP连接失败，重定向过多？

0 个答案: