如果你有话,那我试着把它弄到一个地方#34; man"例如它看起来像_ _ _。如果用户输入" m"它看起来像m _ _。我知道我的问题在于#34;#用户将在哪里输入猜测"在for循环下发表评论 随机导入
user_input = ""
turns = 5
# List of words
print("Welcome to Advanced Hang Man!")
guesses = ["hello"]
# Picks a random word from the list and prints the length of it
random_guesses = (random.choice(guesses))
right_guess = []
wrong_guess = []
# Prints the hidden word in "_" format
hidden_word = "_" * len(random_guesses)
print(hidden_word)
# Where user will type guess
while True:
user_input = input("Please enter a letter once at a time:")
user_input = user_input.lower()
for i in range(len(random_guesses)):
if user_input == random_guesses[i]:
print(hidden_words)
答案 0 :(得分:0)
您需要迭代实际单词并检查right_guesses
列表中的字符。如果找不到,请用新单词中的_
替换该字符。以下是实现此目的的示例代码:
>>> my_word = "StackOverflow"
>>> right_guesses = ['s', 'o', 'c']
>>> ' '.join([word if word.lower() in right_guesses else '_' for word in my_word])
'S _ _ c _ O _ _ _ _ _ o _'
答案 1 :(得分:0)
这是我尝试制作游戏的方法。我没有使用您的right_guesses
列表,也没有使用wrong-guesses
,但它具有悬挂式游戏的基本功能:
user_input = ""
print("Welcome to Advanced Hang Man!")
random_word= 'bicycle'
hidden_word = "_" * len(random_word)
going = True
while going:
print(hidden_word)
user_input = input("Please enter a letter once at a time:");
user_input = user_input.lower()
for i in range(len(random_word)):
if user_input == random_word[i]:
print ('Letter found!')
temp = list(hidden_word)
temp[i] = user_input
hidden_word = ''.join(temp)
if (hidden_word == random_word):
print ('You Won!!! The word was ' + random_word)
going = False