我想打开一个文本文件并完整地阅读它,同时使用c ++将其内容存储到变量和数组中。我的示例文本文件如下。我想将第一行存储到整数变量中,将第二行存储到3d数组索引中,将最后一行存储为字符串数组的5个元素。我知道如何打开文件进行读取但我还没学会如何读取某些单词并将它们存储为整数或字符串类型。我不知道如何在c ++中实现这一点,非常感谢任何帮助。
3
2 3 3
4567 2939 2992 2222 0000
答案 0 :(得分:1)
使用ifstream
std::ifstream input( "filename.txt" );
能够逐行阅读:
for( std::string line; getline( input, line ); )
{
//do what you want for each line input here
}
答案 1 :(得分:1)
阅读文本文件中的所有内容:
#include <fstream>
int main() {
std::ifstream in;
in.open("input_file.txt")
// Fixed size array used to store the elements in the text file.
// Change array type according to the type of the elements you want to read from the file
int v[5];
int element;
if (in.is_open()) {
int i = 0;
while (in >> element) {
v[i++] = element;
}
}
in.close();
return 0;
}
答案 2 :(得分:1)
试试这个:
#include <iostream>
#include <string>
#include <fstream>
int main()
{
std::ifstream file("filename.txt"); // enter the name of your file here
int firstLine;
int secondLine;
const int X = 3;
const int Y = 1;
const int Z = 1;
int ***arr3D;
std::string myArray[5];
std::string myString;
if (file.is_open())
{
// store the first line into an integer variable
file >> firstLine;
// store the second line into a 3d array index
arr3D = new int**[X];
for (int i = 0; i < X; i++)
{
arr3D[i] = new int*[Y];
for (int j = 0; j < Y; j++)
{
arr3D[i][j] = new int[Z];
for (int k = 0; k < Z; k++)
{
file >> secondLine;
arr3D[i][j][k] = secondLine;
}
}
}
// store the final line into 5 elements of a string array
int i = 0;
while (file >> myString)
{
myArray[i] = myString;
i++;
}
}
file.close();
std::cout << firstLine << std::endl;
for (int i = 0; i < X; i++)
{
for (int j = 0; j < Y; j++)
{
for (int k = 0; k < Z; k++)
{
std::cout << arr3D[i][j][k] << std::endl;
}
}
}
for (int i = 0; i < 5; i++)
{
std::cout << myArray[i] << std::endl;
}
return 0;
}