Question

我正在尝试简单的事情，形成一个我希望获得前两名最高员工名单的员工集合。但是请记住，可以有多名员工具有相同的薪水，所以如果他们的薪水范围最大，我希望他们都是。以下是我正在使用的收藏品：

List<Employee> Employees = new List<Employee>
            {
                new Employee {EmployeeID = 1,EmployeeName  ="A", Department ="Dept1", Salary = 10000 },
                new Employee {EmployeeID = 5,EmployeeName  ="A1", Department ="Dept2", Salary = 12000 },
                new Employee {EmployeeID = 2,EmployeeName ="B", Department ="Dept1", Salary = 20000 },
                new Employee {EmployeeID = 3,EmployeeName ="C",  Department ="Dept1", Salary = 20000 },
                new Employee {EmployeeID = 6,EmployeeName ="B1", Department ="Dept2", Salary = 4500 },
                new Employee {EmployeeID = 4,EmployeeName="D",  Department ="Dept1", Salary = 30000 },
            };

和Employee类是：

 public class Employee
    {
        public int EmployeeID { get; set; }
        public string EmployeeName { get; set; }
        public string Department { get; set; }
        public long Salary { get; set; }
    }

以下是我的查询：

var result1 = from x in Employees
                    group x by x.Salary into g
                    from y in g.OrderBy(x=>x.Salary).Take(2)
                    select new { y.EmployeeID };

            foreach (var item in result1)
            {
                Console.WriteLine(item.EmployeeID);
            }

我在这里要做的是，首先我根据他们的工资对所有员工进行分组。然后使用TAKE扩展方法对这些组进行排序并前两组，然后打印这两组中的所有员工。

但我不知道为什么要打印所有员工;它甚至没有订购它们。有人可以分享一些想法并告诉我这个查询有什么问题吗？

Answer 1

您可以先选择不同的最高薪水，然后将其加入员工：

var q =
        from s in Employees.Select(e => e.Salary).Distinct().OrderByDescending(s => s).Take(2)
        from e in Employees.Where(e => e.Salary == s)
        select e;

当有一些冲突时，Linq查询返回前两个结果，是不是有效？

1 个答案: