Question

如何看代码，以下脚本只在06.30h和8.00h之间运行？最好的问候

#!/usr/bin/python


from time import strftime    
import sys    
import subprocess from subprocess    
import Popen    
import pifacedigitalio    
from time import sleep


pfd = pifacedigitalio.PiFaceDigital() # creates a PiFace Digital 
object testprocess = None

while strftime('%H:%M') >= '06:29':
    while(True):
        sleep(0.1)
        if pfd.input_pins[0].value == 1 and not testprocess:
            subprocess.Popen(["/bin/myscript"])
            testprocess = Popen(["/bin/myscript1"])
            if pfd.input_pins[0].value == 0:
                if testprocess:
                    testprocess.kill()
                    testprocess = None
                    subprocess.Popen(["/bin/mycript"])
            sleep(1)
            if strftime('%H:%M') == '08:00':
                sys.exit()

Answer 1

我会这样做：

This is my overridden greeting message
This shape is a Circle

您可以在此处详细了解时间模块：https://docs.python.org/2/library/time.html

Answer 2

只需花时间进入时间结构并计算从午夜开始的分钟数，以分钟为单位测试时间窗口：

lt = time.localtime()
minutes = 60*lt.tm_hour + lt.tm_min
if 60*6+30 <= minutes <= 60*8:
    subprocess.Popen(["/bin/myscript"])
    testprocess = Popen(["/bin/myscript1"])

Python脚本只能在时间窗口中运行

2 个答案: