Question

我有一个数组如下

{ “contractID”：27112016185818 “contractName”： “DDF”， “供应商ID”：5 “supplierName”： “HH”， “的productID”：44， “产品名称”： “GG”， “计量单位”： “UU”， “数量”：6， “pricePerUOM”：6， “totalPrice”：36， “货币”： “INR”， “supplyByDate”： “01112016”， “createdDate”： “27112016”， “loginuser”： “买方”， “chain_id”： “supplychainintegrity”， “高度”：244432 “num_txs”：1， “pendingWith”： “”， “block_hash”： “散列”， “block_data”： “数据”， “data_hash” ： “datahash”， “block_time”： “时间”}

我想将其转换为以下内容

[{"contractID":27112016185818,"contractName":"ddf","supplierID":5,"supplierName":"hh","productID":44,"productName":"gg","uom":"uu","quantity":6,"pricePerUOM":6,"totalPrice":36,"currency":"inr","supplyByDate":"01112016","createdDate":"27112016","loginuser":"buyer","chain_id":"supplychainintegrity","height":244432,"num_txs":1,"pendingWith":"","block_hash":"hash","block_data":"data","data_hash":"datahash","block_time":"time"}]

用于json字符串化。

jsonObj["row"]=currentArray;
newArray=JSON.stringify(jsonObj);

我的newArray如下

{"row":{"contractID":27112016185818,"contractName":"ddf","supplierID":5,"supplierName":"hh","productID":44,"productName":"gg","uom":"uu","quantity":6,"pricePerUOM":6,"totalPrice":36,"currency":"inr","supplyByDate":"01112016","createdDate":"27112016","loginuser":"buyer","chain_id":"supplychainintegrity","height":244432,"num_txs":1,"pendingWith":"","block_hash":"hash","block_data":"data","data_hash":"datahash","block_time":"time"}}

需要如下

{ “行”：[{ “contractID”：27112016185818 “contractName”： “DDF”， “供应商ID”：5 “supplierName”： “HH”， “的productID”：44， “产品名称”：“GG “ ”计量单位“： ”UU“， ”数量“：6， ”pricePerUOM“：6， ”totalPrice“：36， ”货币“： ”INR“， ”supplyByDate“： ”01112016“， ”createdDate“：” 27112016 “ ”loginuser“： ”买方“， ”chain_id“： ”supplychainintegrity“， ”高度“：244432 ”num_txs“：1， ”pendingWith“： ”“， ”block_hash“： ”散列“， ”block_data“：”数据”， “data_hash”： “datahash”， “block_time”： “时间”}]}

Answer 1

你可以这么做，

 $scope.newarray = [];
 $scope.myObj = data.row;
 $scope.newarray.push($scope.myObj);
 console.log($scope.newarray);

<强> DEMO

数组格式错误

1 个答案: