Question

我有2个实体和投影的休息库：

@Entity
public class Person {
    @Id
    @GeneratedValue
    private Long id;

    String name;

    @ManyToOne
    Language language;
}

@Entity
public class Language {
    @Id
    @GeneratedValue
    private Long id;

    private String name;
}

public interface PersonRepository extends PagingAndSortingRepository<Person, Long> {
}

@Projection(name = "details", types = {Person.class})
interface PersonProjection {

    Long getId();

    String getName();

    @Value("#{target.language.name}")
    String getLanguage();
}

当我尝试按语言字段对其进行排序时

/ API /人/投影=细节＆安培;排序=语言

它会生成尝试按language.id

对其进行排序的SQL

选择person0_.id作为我...按 language1_.id asc限制排序？

有没有办法告诉Spring Data，JPA使用不同的默认属性进行排序而不在url中明确指定它？

Answer 1

配置Spring数据时，它会在实体对象上使用属性遍历。在您的情况下，对于人员和语言，您在属性“名称”上有名称冲突。为了解决这个问题，你的sort param应该引用正确的属性，即：对于按语言名称排序，您的网址应为/ api / persons /？projection = details＆amp; sort = language_name 按人名排序你的url参数shoud look / api / persons /？projection = details＆amp; sort = person_name

Answer 2

首先覆盖import Vapor import Fluent import Foundation final class Store: Model { // MARK: - Model var id: Node? var exists: Bool = false var locationIDs: [Node] = [] // No idea if this is right var name: String init(name: String, locationIDs: [Node] = []) { self.id = nil self.name = name self.locationIDs = locationIDs } init(node: Node, in context: Context) throws { id = try node.extract("id") name = try node.extract("name") // ??? } func makeNode(context: Context) throws -> Node { return try Node(node: [ "id": id, "name": name // ??? ]) } static func prepare(_ database: Database) throws { try database.create( "stores" ) { creator in creator.id() creator.string("name") // creator.id("", optional: false) // ??? } } static func revert(_ database: Database) throws { try database.delete("stores") } }界面中的findAll()方法：

PersonRepository

然后将命名查询添加到public interface PersonRepository extends PagingAndSortingRepository<Person, Long> { @Override @Query public Iterable<User> findAll(); }实体类：

User

在JPQL中按顺序定义引用字段的排序属性

2 个答案: