Question

我正在使用Python 3.5空闲。我在使用elif函数时出现缩进错误。这是我输入的代码：

>>> num = 7

>>> if num == 5:

    print("number is 5")

... elif num == 11:

  File "<stdin>", line 2

    elif num == 11:
       ^
IndentationError: expected an indented block

Answer 1

您需要在elif之后编写一些代码。例如：

>>> num = 7
>>> if num == 5:
...     print("Number is 5")
... elif num == 11:
...     print("Number is 11")
...
>>> if num == 5:
...     print("Number is 5")
... elif num == 11:
...     print("Number is 11")
... elif num == 7:
...     print("Number is 7")
...
Number is 7
>>>

在elif num == 11:

之后按Enter键会发生这种情况

>>> if num == 5:
...     print("Number is 5")
... elif num == 11:
...
  File "<stdin>", line 4

    ^
IndentationError: expected an indented block
>>>

如果您因某些原因不想做任何事情，请使用pass

>>> num = 11
>>> if num == 5:
...     print("Number is 5")
... elif num == 11:
...     pass
... elif num == 7:
...     print("Number is 7")
...
>>>

Answer 2

检查以确保您使用标签用于缩进或空格，并确保缩进是相同类型。

elif python 3.5中的缩进错误

2 个答案: