问题背景

Question

问题背景

您好，我有以下电影摄制组成员：

array:7 [▼
  0 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5e9d"
    "department" => "Directing"
    "id" => 139098
    "job" => "Director"
    "name" => "Derek Cianfrance"
    "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg"
  ]
  1 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5ed7"
    "department" => "Writing"
    "id" => 139098
    "job" => "Story"
    "name" => "Derek Cianfrance"
    "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg"
  ]
  2 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5edd"
    "department" => "Writing"
    "id" => 132973
    "job" => "Story"
    "name" => "Ben Coccio"
    "profile_path" => null
  ]
  3 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5ee3"
    "department" => "Writing"
    "id" => 139098
    "job" => "Screenplay"
    "name" => "Derek Cianfrance"
    "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg"
  ]
  4 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5ee9"
    "department" => "Writing"
    "id" => 132973
    "job" => "Screenplay"
    "name" => "Ben Coccio"
    "profile_path" => null
  ]
  5 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5eef"
    "department" => "Writing"
    "id" => 1076793
    "job" => "Screenplay"
    "name" => "Darius Marder"
    "profile_path" => null
  ]
  11 => array:6 [▼
    "credit_id" => "52fe49de9251416c750d5f13"
    "department" => "Camera"
    "id" => 54926
    "job" => "Director of Photography"
    "name" => "Sean Bobbitt"
    "profile_path" => null
  ]
]

正如您所看到的，这是我通过TMDb API获得的信用列表。构建上述数组的第一步是过滤掉我不想显示的所有作业，这是我如何做到的：

$jobs = [ 'Director', 'Director of Photography', 'Cinematography', 'Cinematographer', 'Story', 'Short Story', 'Screenplay', 'Writer' ];

$crew = array_filter($tmdbApi, function ($crew) use ($jobs) {
    return array_intersect($jobs, $crew);
});

我的问题

我想弄清楚如何进一步采取上述结果并将jobs与id相同，以便最终得到类似的内容，例如：

array:7 [▼
  0 => array:6 [▼
    "credit_id" => "52fe49dd9251416c750d5e9d"
    "department" => "Directing"
    "id" => 139098
    "job" => "Director, Story, Screenplay"
    "name" => "Derek Cianfrance"
    "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg"
  ]

我也考虑过在我的逻辑中放弃这样做，而是在我的刀片模板中做这件事，但我不知道如何实现这一点。

你将如何实现这一目标？

Answer 1

由于您尝试编辑数组元素及其大小，我相信#include <stdio.h> #include <stdlib.h> char get_letter(char *str, int idx) { return *(str + idx); } int main() { char s[] = "Barack"; printf("%c", get_letter(s,2)); return 0; }或array_map()不会解决此问题。

这就是我能想到的......

array_filter()

希望这能回答你的问题：）

Answer 2

在这种情况下你可以很好地使用Laravel的Collection，它有很多方法可以帮助你。

首先，将此数组（已在作业上过滤的数组）转换为集合：

$collection = collect($crew);

其次，按照id s：

对此集合进行分组

$collectionById = $collection->groupBy('id');

现在，结果按分组id并转换为一个集合，其中键对应于id，值为数组'匹配'结果。有关它的更多信息here。

最后，只是一个简单的脚本，遍历每个id的所有结果，并结合job字段：

$combinedJobCollection = $collectionById->map(function($item) {
    // get the default object, in which all fields match
    // all the other fields with same ID, except for 'job'
    $transformedItem = $item->first();

    // set the 'job' field according all the (unique) job
    // values of this item, and implode with ', '
    $transformedItem['job'] = $item->unique('job')->implode('job', ', ');

    /* or, keep the jobs as an array, so blade can figure out how to output these
    $transformedItem['job'] = $item->unique('job')->pluck('job');
    */

    return $transformedItem;
})->values();
// values() makes sure keys are reordered (as groupBy sets the id
// as the key)

此时，将返回此Collection：

Collection {#151 ▼
  #items: array:4 [▼
    0 => array:6 [▼
      "credit_id" => "52fe49dd9251416c750d5e9d"
      "department" => "Directing"
      "id" => 139098
      "job" => "Director, Story, Screenplay"
      "name" => "Derek Cianfrance"
      "profile_path" => "/zGhozVaRDCU5Tpu026X0al2lQN3.jpg"
    ]
    1 => array:6 [▼
      "credit_id" => "52fe49dd9251416c750d5edd"
      "department" => "Writing"
      "id" => 132973
      "job" => "Story, Screenplay"
      "name" => "Ben Coccio"
      "profile_path" => null
    ]
    2 => array:6 [▼
      "credit_id" => "52fe49dd9251416c750d5eef"
      "department" => "Writing"
      "id" => 1076793
      "job" => "Screenplay"
      "name" => "Darius Marder"
      "profile_path" => null
    ]
    3 => array:6 [▼
      "credit_id" => "52fe49de9251416c750d5f13"
      "department" => "Camera"
      "id" => 54926
      "job" => "Director of Photography"
      "name" => "Sean Bobbitt"
      "profile_path" => null
    ]
  ]
}

注意：要将此Collection用作数组，请使用：

$crew = $combinedJobCollection->toArray();

有多种方法可以实现这一点，例如：search用于重叠id的数组，但我认为这是实现此目的的最简单方法。

古德勒克！

根据同一数组

问题背景

我的问题

2 个答案: