Question

我尝试根据下拉列表中的选定值添加输入字段。我想在//Get the recipient a user wants to send message if(isset($_POST['recipname']) && !empty($_POST['recipname'])){ $recipname = mysqli_real_escape_string($dbc_conn,trim($_POST['recipname'])); $recipname = preg_replace('/\s+/', ' ',$recipname); $sql = " SELECT id, username,firstname , lastname , avatar , school FROM $table_name WHERE CONCAT('%', firstname,' ',lastname,'%') LIKE '%$recipname%' OR CONCAT('%', lastname,' ',firstname,'%') LIKE '%$recipname%' LIMIT 6 "; //Query database }上附加输入字段。我真的尝试了很多，但我找不到错误。也许这个社区中的某个人已经看到了它......

＆＃13;

<div>

＆＃13;

$(document).ready(function () {
    //Initialize tooltips
    $('.nav-tabs > li a[title]').tooltip();
    
    //Wizard
    $('a[data-toggle="tab"]').on('show.bs.tab', function (e) {

        var $target = $(e.target);
    
        if ($target.parent().hasClass('disabled')) {
            return false;
        }
    });

    $(".next-step").click(function (e) {

        var $active = $('.wizard .nav-tabs li.active');
        $active.next().removeClass('disabled');
        nextTab($active);

    });
    $(".prev-step").click(function (e) {

        var $active = $('.wizard .nav-tabs li.active');
        prevTab($active);

    });
    
   // $(document).on('ready', function() {
   // $("#input-4").fileinput({showCaption: false});
//});
});

function nextTab(elem) {
    $(elem).next().find('a[data-toggle="tab"]').click();
}
function prevTab(elem) {
    $(elem).prev().find('a[data-toggle="tab"]').click();
}


//according menu

$(document).ready(function()
{
    //Add Inactive Class To All Accordion Headers
    $('.accordion-header').toggleClass('inactive-header');
	
	//Set The Accordion Content Width
	var contentwidth = $('.accordion-header').width();
	$('.accordion-content').css({});
	
	//Open The First Accordion Section When Page Loads
	$('.accordion-header').first().toggleClass('active-header').toggleClass('inactive-header');
	$('.accordion-content').first().slideDown().toggleClass('open-content');
	
	// The Accordion Effect
	$('.accordion-header').click(function () {
		if($(this).is('.inactive-header')) {
			$('.active-header').toggleClass('active-header').toggleClass('inactive-header').next().slideToggle().toggleClass('open-content');
			$(this).toggleClass('active-header').toggleClass('inactive-header');
			$(this).next().slideToggle().toggleClass('open-content');
		}
		
		else {
			$(this).toggleClass('active-header').toggleClass('inactive-header');
			$(this).next().slideToggle().toggleClass('open-content');
		}
	});
	
	return false;
});

＆＃13;

Answer 1

没有标识为std::string的元素，但有一个test1。

你的附加语句也会提前关闭，所以你有一系列以逗号分隔的语句。

所以

test

$("#test1").append($("<label/>").text(i + ". Division Name"))
                                        //move this bracket ^
...
}), $("<br/>"), $("<br/>");
        //and put it here ^

$("#test").append($("<label/>").text(i + ". Division Name"), $("<input/>", {
    class: 'form-control',
    type: 'text',
    name: 'name_' + i
}), $("<br/>"), $("<input/>", {
    type: 'text',
    value: sel_value,
    name: 'NumbDiv_' + i
}), $("<br/>"), $("<br/>"));

$(document).ready(function () {
    $('select#selectDiv').change(function () {
        var sel_value = $(this).val();

        if (sel_value == 0) {
            $("#test").empty(); // Resetting Form
        }
        else {
            $("#test").empty(); //Resetting Form
            create(sel_value);
        }
    });
function create(sel_value) {
    for (var i = 1; i <= sel_value; i++) {
        $("#test").append($("<label/>").text(i + ". Division Name"), $("<input/>", {
            class: 'form-control',
            type: 'text',
            name: 'name_' + i
        }), $("<br/>"), $("<input/>", {
            type: 'text',
            value: sel_value,
            name: 'NumbDiv_' + i
        }), $("<br/>"), $("<br/>"));
    }
}
});

Answer 2

我发现了我的错误......我必须在选择选项之前插入ID var sel_value = $（＆＃39; option：selected＆＃39;）。val（）;

更正：var sel_value = $（＆＃39; #selectDiv选项：已选择＆＃39;）。val（）;

使用jquery基于所选值添加inputfield

2 个答案: