我正在使用JavaScript和HTML5制作Numerology转换网络应用程序。我遇到了一个变量和循环的奇怪问题。以下是我目前形式的整个项目。
<limits>所以基本上你把你的生日和全名输入表格。然后，脚本将名称转换为数字A = 1，B = 2 ....并将两者都减少为单个数字。这些数字将逐一添加。例。 13 = 4,55 = 10,63 = 9。
以下是用于进行缩减的一般代码。我们让PODN = 55
> clang++ --version
Apple LLVM version 8.0.0 (clang-800.0.42.1)
$ g++ --version
g++ (Debian 4.9.2-10) 4.9.2
目前，它只循环一次，但我希望将其减少到可能的最低数量。在这种情况下为1。我在想，如果我将if改变一段时间它会完成这个但是它不会像我想象的那样工作。我试图做一些改变并陷入困境。所以我开始排除故障。我添加了另一个变量来防止整个循环无限循环。
<html>
<body>
<h1>My First Numerology Project</h1>
<form>
Month:<br>
<input type="text" maxlength="2" name="userInputMonth" id='userInputMonth'>
<br>
Day:<br>
<input type="text" maxlength="2" name="userInputDay" id='userInputDay'>
<br>
Year:<br>
<input type="text" maxlength="4" name="userInputYear" id='userInputYear'>
<br><br>
First Name:<br>
<input type="text" name="userInputFirstName" id='userInputFirstName'>
<br>
Middle Name:<br>
<input type="text" name="userInputMiddleName" id='userInputMiddleName'>
<br>
Last Name:<br>
<input type="text" name="userInputLastName" id='userInputLastName'>
<br><br>
<input type="button" value="Calculate" name="Calculate" onclick="BirthDayCalculation()"/>
</form>
<p id="LLNResult"></p>
<br>
<p id="OPNResult"></p>
<br>
<p id="SNResult"></p>
<br>
<p id="PODNResult"></p>
<script type="text/javascript">
//Defined var
var LLNTemp1;
var LLNTemp2;
var LLNReduce1;
var LLNReduce2;
var NameTemp1;
var NameTemp2;
var OPNReduce1;
var OPNReduce2;
var SNReduce1;
var SNReduce2;
var PODNReduce1;
var PODNReduce2;
function BirthDayCalculation() {
var Reduction1 = 0;
var LLNReduceFinal2 = 0;
var Day = document.getElementById('userInputDay').value;
var Month = document.getElementById('userInputMonth').value;
var Year = document.getElementById('userInputYear').value;
var FirstName = document.getElementById('userInputFirstName').value;
var MiddleName = document.getElementById('userInputMiddleName').value;
var LastName = document.getElementById('userInputLastName').value;
var LLN = ("" + Day + Month + Year).toString();
var FullName = ("" + FirstName + MiddleName + LastName).toString().toUpperCase();
var FullNameLength = parseInt(FullName.length);
var LLNLength = parseInt(("" + Day + Month + Year).length);
var i = 0;
var LLNTemp2 = 0;
while (i < LLNLength) {
LLNTemp1 = parseInt(LLN.charAt(i));
LLNTemp2 += LLNTemp1;
i++;
}
if (LLNTemp2 > 9) {
var i = 0;
var a = parseInt(LLNTemp2.toString().length);
var LLNReduceFinal1 = 0;
var LLNTemp3String = LLNTemp2.toString();
while (i < a) {
LLNReduce1 = parseInt(LLNTemp3String.charAt(i));
LLNReduceFinal1 += LLNReduce1;
i++;
}
var LLNReduceFinal2 = 0;
var Reduction1 = LLNReduceFinal1;
if (LLNReduceFinal1 > 9) {
var i = 0;
var a = parseInt(Reduction1.toString().length);
var LLNTemp3String = Reduction1.toString();
while (i < a) {
LLNReduce1 = parseInt(LLNTemp3String.charAt(i));
LLNReduceFinal2 += LLNReduce1;
i++;
}
}
}
var OPN = 0;
var SN = 0;
var PODN = 0;
var PODNWhole = 0;
var i = 0;
while (i < FullNameLength) {
NameTemp1 = FullName.charAt(i);
var OPNTemp = 0;
var SNTemp = 0;
if (NameTemp1 == "A") SNTemp = 1;
if (NameTemp1 == "J" || NameTemp1 == "S") OPNTemp = 1;
if (NameTemp1 == "B" || NameTemp1 == "K" || NameTemp1 == "T") OPNTemp = 2;
if (NameTemp1 == "C" || NameTemp1 == "L") OPNTemp = 3;
if (NameTemp1 == "U") SNTemp = 3;
if (NameTemp1 == "D" || NameTemp1 == "M" || NameTemp1 == "V") OPNTemp = 4;
if (NameTemp1 == "E") SNTemp = 5;
if (NameTemp1 == "N" || NameTemp1 == "W") OPNTemp = 5;
if (NameTemp1 == "F" || NameTemp1 == "X") OPNTemp = 6;
if (NameTemp1 == "O") SNTemp = 6;
if (NameTemp1 == "G" || NameTemp1 == "P" || NameTemp1 == "Y") OPNTemp = 7;
if (NameTemp1 == "H" || NameTemp1 == "Q" || NameTemp1 == "Z") OPNTemp = 8;
if (NameTemp1 == "I") SNTemp = 9;
if (NameTemp1 == "R") OPNTemp =9;
OPN += OPNTemp;
SN += SNTemp;
PODNWhole += SNTemp;
PODNWhole += OPNTemp;
i++;
}
var PODN = PODNWhole
var OPNReduceFinal = 0;
if (OPN > 9) {
var OPNLength = parseInt(OPN.toString().length);
var OPNTempString = OPN.toString();
var i = 0;
while (i < OPNLength) {
OPNReduce1 = parseInt(OPNTempString.charAt(i));
OPNReduceFinal += OPNReduce1;
i++;
}
}
var SNReduceFinal = 0;
if (SN > 9) {
var SNLength = parseInt(SN.toString().length);
var SNTempString = SN.toString();
var i = 0;
while (i < SNLength) {
SNReduce1 = parseInt(SNTempString.charAt(i));
SNReduceFinal += SNReduce1;
i++;
}
}
var PODNReduceFinal = 0;
if (PODN > 9) {
var PODNLength = parseInt(PODN.toString().length);
var PODNTempString = PODN.toString();
var i = 0;
while (i < PODNLength) {
PODNReduce1 = parseInt(PODNTempString.charAt(i));
PODNReduceFinal += PODNReduce1;
i++;
}
// var PODNReduceFinal = PODNReduce2;
// var PODN = PODNReduce2;
}
var LLNResult = "Your Life Lesson Number Is:" + LLNTemp2 + "/" + Reduction1;
if (LLNReduceFinal2 != 0) {
LLNResult = LLNResult + "/" + LLNReduceFinal2;
}
var OPNResult = "Your Outer Personality Number is:" + OPN;
if (OPNReduceFinal != 0) {
var OPNResult = OPNResult + "/" + OPNReduceFinal;
}
var SNResult = "Your Soul Number is:" + SN;
if (SNReduceFinal != 0) {
var SNResult = SNResult + "/" + SNReduceFinal;
}
var PODNResult = "Your Path of Destiny Number is:" + PODNWhole;
if (PODNReduceFinal != 0) {
var PODNResult = PODNResult + "/" + PODNReduceFinal;
}
if (LLNTemp2 != 0) {
document.getElementById("LLNResult").innerHTML = LLNResult;
}
if (PODNWhole != 0) {
document.getElementById("OPNResult").innerHTML = OPNResult;
document.getElementById("SNResult").innerHTML = SNResult;
document.getElementById("PODNResult").innerHTML = PODNResult;
}
}
</script>
</body>
</html>
使用这个我认为当PODN首先被while循环检查时，它会完成第一步。获取数字的长度，在这种情况下2.将其转换为字符串，以便它可以逐个拉出数字。按循环长度顺序拉数字并将其转换为数字。在PODNReduce2,55 = 10中将它们一起添加。设置PODNReduceFinal = 10，设置PODN = 10.然后返回第一个条件并检查PODN现在是10并且大于9.再次循环以进一步减小。这样做直到它存储在PODNReduceFinal中的单个数字。但事实并非如此。当我尝试显示PODNReduceFinal时，我得到了NaN。即使我将第一个“while”恢复为“if”，它仍然无效。我不知所措。请帮忙。