我有XML字符串,它有多个子节点,我想从下面的子节点获取数据是一个示例结构,我想获取所有结果节点。尝试在 MySQL
中使用此查询SET @xml= '<aaa><result>
<id>1</id>
</result>
<result>
<id>2</id>
</result>
....
</aaa>';
SELECT ExtractValue(@xml, '/aaa/result/id/text()[1]');
当前输出
1 2
预期输出
1
2
如果有最好的方法可以告诉我吗?
答案 0 :(得分:1)
我是通过将列分成两列
来实现的SET @xml= '<aaa><result>
<id>1</id>
</result>
<result>
<id>2</id>
</result>
</aaa>';
SELECT
SUBSTRING_INDEX(ExtractValue(@xml, '//id'), ' ', 1) AS `id1`,
SUBSTRING_INDEX(ExtractValue(@xml, '//id'), ' ', -1) AS `id2`
<强>输出强>
id1 | id2
1 | 2
正如你所说的结果节点可以是多个,为此我尝试了下面的查询
SET @xml= '<aaa><result>
<id>1</id>
</result>
<result>
<id>2</id>
</result>
<result>
<id>3</id>
</result>
<result>
<id>4</id>
</result>
<result>
<id>5</id>
</result>
<result>
<id>7</id>
</result>
<result>
<id>6</id>
</result>
<result>
<id>8</id>
</result>
<result>
<id>9</id>
</result>
<result>
<id>10</id>
</result>
<result>
<id>11</id>
</result>
</aaa>';
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(ExtractValue(@xml, '//id'), ' ', n.n), ' ', -1) value
FROM (select SUBSTRING_INDEX(ExtractValue(@xml, '//id'), ' ', 1)) t CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(ExtractValue(@xml, '//id')) - LENGTH(REPLACE(ExtractValue(@xml, '//id'), ' ', '')))
<强>输出强>
Value
1
2
3
4
5
7
6
8
9
11