Question

我的python代码需要帮助。我一直试图将输入的句子保存到文本文件中而不重复文件中的单词。我不知道该怎么做。

感谢任何帮助。

这是我的代码：

import sys

#user-friendly, informs the user what do to
answer = input("What is your name?\n")
print("Hello " + answer + " and welcome to this program!\n")
print("This program will ask you for a sentence and print out the positions of the words instead of the actual words. it will then save it in a file with the sentence.\n")

repeat = True
loop = True
true = True

#Allows the user to decide whether or not they want to use the program
while repeat:
    answer2 = input("Do you want to do run this program?\n")
    #if the answer is 'no' then the program stops
    if answer2.lower() == "No" or answer2.lower() == "nah" or answer2.lower() == "no" or answer2.lower() == "n":
        print ("Okay then ... Bye.")
        sys.exit()
    #if the answer is 'yes' then the code continues
    elif answer2 == "Yes".lower() or answer2.lower() == "yeah" or answer2.lower() == "yes" or answer2.lower() == "y":
        print ("Okay then ... \n")
        while true:
            if loop == True:
                sentence = input("Please enter a sentence:\n").lower()
            #converts the sentence into a list
            s = sentence.split()
            #works out the positions of the words
            positions = [s.index(x)+1 for x in s]
            print(positions)

            #opens a text file
            fi = open("CA Task 2.txt", "w")
            #Allows you to write over  the original content in the file
            fi.write(str(s))
            #it closes the file once you've finished with it
            fi.close()

            #opens a text file
            fi = open("CA Task 2.txt", "a")
            #Allows you to add to the text file instead of writing over it
            fi.write("\n")
            fi.write(str(positions))
            #it closes the file once you've finished with it
            fi.close()
            sys.exit()

    #if the answer is neither 'yes' nor 'no' then the programs jumps to this part and allows the user to try again
    else:
        print("Please enter a valid answer! Try again!\n")

我们只是说输入的句子是“不要问你的国家能为你做些什么，而是要为你的国家做些什么”。

应该说：不要问你的国家能为你做些什么，而是要为你的国家做些什么

[1,2,3,4,5,6,7,8,9,10,3,9,6,7,8,4,5]

这有效，然后必须保存到文本文件中： ['问'，'不'，'什么'，'你的'，'国家'，'能'，'做'，'为'，'你'，'但'，'什么'，'你'，'可以'，'做'，'为'，'你'，'国家']

[1,2,3,4,5,6,7,8,9,10,3,9,6,7,8,4,5]

这很好但我想要它做的是如果在文本文件中已经提到过一次，就不要重复这个词。

Answer 1

内置了一个名为set https://docs.python.org/3/library/stdtypes.html#set的函数：

import sys

 #user-friendly, informs the user what do to
 answer = input("What is your name?\n")
 print("Hello " + answer + " and welcome to this program!\n")
 print("This program will ask you for a sentence and print out the positions of the words instead of the actual words. it will then save it in a file with the sentence.\n")

repeat = True
loop = True
true = True

 #Allows the user to decide whether or not they want to use the program
 while repeat:
  answer2 = input("Do you want to do run this program?\n")
  #if the answer is 'no' then the program stops
  if answer2.lower() == "No" or answer2.lower() == "nah" or answer2.lower() ==    "no" or answer2.lower() == "n":
    print ("Okay then ... Bye.")
    sys.exit()
#if the answer is 'yes' then the code continues
elif answer2 == "Yes".lower() or answer2.lower() == "yeah" or answer2.lower() == "yes" or answer2.lower() == "y":
    print ("Okay then ... \n")
    while true:
        if loop == True:
            sentence = input("Please enter a sentence:\n").lower()
        # converts the sentence into a list
        s = sentence.split()
        # for loop makes sure that if the word is in the list then it wont print it out again
        for word in s:
            if word not in s:
                s.append(word)
        # works out the positions of the words
        positions = [s.index(x) + 1 for x in s]
        print(set(positions))

        # opens a text file
        fi = open("CA Task 2.txt", "w")
        # Allows you to write over  the original content in the file
        fi.write(str(set(s)))
        # it closes the file once you've finished with it
        fi.close()

        # opens a text file
        fi = open("CA Task 2.txt", "a")
        # Allows you to add to the text file instead of writing over it
        fi.write("\n")
        fi.write(str(set(positions)))
        # it closes the file once you've finished with it
        fi.close()
        sys.exit()

        #if the answer is neither 'yes' nor 'no' then the programs jumps to this part and allows the user to try again
        else:
         print("Please enter a valid answer! Try again!\n")'

Answer 2

所以这是你的for循环部分没有表现？当我将一个句子分成一个列表['here', 'is', 'my', 'sentence', 'input']然后循环遍历每个单词并将它们追回到列表中时（如果它们尚未包含在内）中。所以这对s永远不会有任何影响。

Python有一个set集合，它包含唯一值。所以它就像list但不允许你添加重复项。您可以使用此代替for for循环，因为您可以使用set初始化list - 就像用户通过split()调用创建的那样。

s = sentence.split()
s = set(s)

编辑：集合不像list那样保留顺序。因此，如果按照首次出现的顺序保存单词很重要，那么此方法将无效。

Answer 3

此：

for word in s:
    if word not in s:
        s.append(word)

对我没有意义。您是否尝试创建一个独特单词列表？它给你相同的清单。

同样if answer2.lower() == "No"是超级流行音乐，因为结果永远不会是＆＃39; No＆＃39;。

让我们说，你有一个句子的列表，其中一些单词是唯一的，有些不是： s = ['foo', 'bar', 'foo', 'foo', 'spam'] 并且你想获得这些独特单词的数字表示，你可以这样得到它：

d = []
i = 0
for item in s:
    if item not in s[:i]:
        d.append(i)
        i += 1
    else:
        d.append(s.index(item))

现在你得到一个列表，其中每个数字是s中单词的唯一表示：

[0, 1, 0, 0, 2]

Answer 4

更改检查单词是否在s中的部分。您应该将您的单词保存在另一个列表中，并检查s单词是否已经在另一个列表中。如下面的代码所示：

#for loop makes sure that if the word is in the list then it wont print it out again
    new_s = []
    for word in s:
       if word not in new_s:
           new_s.append(word)

Python代码 - 不确定文本文件

4 个答案: