好的,所以我在创建附加表时遇到了问题,最初我创建了一个名为Contacts的表,它运行良好。
然后我将另一个表Message集成到我要创建的DBHandler中的onCreate方法中,这是我开始遇到问题的时候。
首先,logcat会拒绝甚至给出一个错误,为什么它不能正常工作,然后我从我的avd中删除了程序以启动一个全新的数据库文件夹,以防这是问题,现在它在我的表消息附近发出语法错误,我也改变了我的DBVersion号。
这是我的DBHandler,我相信问题是在onCreate方法中发生的,带有Create messages表。
private static final int DATABASE_VERSION = 2;
private static final String COLUMN_ID = "id";
private static final String DATABASE_NAME = "forensicsproject";
//====================================================
private static final String TABLE_CONTACTS = "contacts";
private static final String CONTACTS_COLUMN_NAME = "name";
private static final String CONTACTS_COLUMN_PHONENUMBER = "phone_number";
//====================================================
private static final String TABLE_MESSAGES = "messages";
private static final String MESSAGES_COLUMN_PERSON = "person";
private static final String MESSAGES_COLUMN_BODY = "body";
private static final String MESSAGES_COLUMN_ADDRESS = "address";
private static final String MESSAGES_COLUMN_TYPE = "type";
//private static final MESSAGES_COLUMN_DATE = "date"; //TODO
public DBHandler(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
String CREATE_CONTACTS_TABLE = "CREATE TABLE " + TABLE_CONTACTS + "("
+ COLUMN_ID + " INTEGER PRIMARY KEY," + CONTACTS_COLUMN_NAME + " TEXT,"
+ CONTACTS_COLUMN_PHONENUMBER + " TEXT" + ")";
db.execSQL(CREATE_CONTACTS_TABLE);
Log.e("CONTACT", "CREATED");
String CREATE_MESSAGES_TABLE = "CREATE TABLE" + TABLE_MESSAGES + "("
+ COLUMN_ID + " INTEGER PIMRARY KEY," + MESSAGES_COLUMN_PERSON + " TEXT,"
+ MESSAGES_COLUMN_BODY + " TEXT," + MESSAGES_COLUMN_ADDRESS + " TEXT,"
+ MESSAGES_COLUMN_TYPE + " TEXT" + ")";
db.execSQL(CREATE_MESSAGES_TABLE);
Log.e("MESSAGES", "CREATED");
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
db.execSQL("DROP TABLE IF EXISTS " + TABLE_CONTACTS + TABLE_MESSAGES);
onCreate(db);
}
public void addContact(Contact contact) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(CONTACTS_COLUMN_NAME, contact.getName());
values.put(CONTACTS_COLUMN_PHONENUMBER, contact.getPhoneNumber());
db.insert(TABLE_CONTACTS, null, values);
Log.e("CONTACTS", "INSERTED");
db.close();
}
public void getMessages(Messages messages) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(MESSAGES_COLUMN_PERSON, messages.getPerson());
values.put(MESSAGES_COLUMN_BODY, messages.getBody());
values.put(MESSAGES_COLUMN_ADDRESS, messages.getAddress());
values.put(MESSAGES_COLUMN_TYPE, messages.getType());
db.insert(TABLE_MESSAGES, null, values);
Log.e("MESSAGES", "INSERTED");
db.close();
}
}
答案 0 :(得分:2)
您的代码中有一些拼写错误:
String CREATE_MESSAGES_TABLE = "CREATE TABLE" + TABLE_MESSAGES + "("
+ COLUMN_ID + " INTEGER PIMRARY KEY," + MESSAGES_COLUMN_PERSON + " TEXT,"
+ MESSAGES_COLUMN_BODY + " TEXT," + MESSAGES_COLUMN_ADDRESS + " TEXT,"
+ MESSAGES_COLUMN_TYPE + " TEXT" + ")";
正如某人已经指出的那样,您需要将其设为 PRIMARY
KEY
,但您还需要为"CREATE TABLE" +
添加空格,以便
"CREATE TABLE " +
。
答案 1 :(得分:0)
String CREATE_MESSAGES_TABLE = "CREATE TABLE" + TABLE_MESSAGES + "(" + COLUMN_ID + " INTEGER PIMRARY KEY," + MESSAGES_COLUMN_PERSON + " TEXT," + MESSAGES_COLUMN_BODY + " TEXT," + MESSAGES_COLUMN_ADDRESS + " TEXT," + MESSAGES_COLUMN_TYPE + " TEXT" + ")";
我猜你的意思是 PRIMARY