Question

我做了一个练习，说：

写一个程序，可以将字母与单词分开，然后用Alpha Bravo Charlie Delta Echo Foxtrot Golf Hotel取代字母Juliet Kilo Lima Mike 11月Oscar Papa魁北克罗密欧Sierra Tango制服Victor Whiskey Xray Yankee Zulu（a = Alpha B = bravo等）和带*的数字（1 = * 2 = ** 3 = ***等）。

让我们说我要打破句子＆＃34;你好2你！＆＃34;。

我希望我的程序返回：

Hotel Echo Lima Lima Oscar ** Yankee Oscar Uniform!.

如何编写程序来执行此操作？

Answer 1

以下程序只是众多可能的一项，应该为您提供解决方案的想法：

#include <stdio.h>
#include <memory.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>

char * alphaTable[] = {
"Alpha",
"Bravo",
"Charlie",
"Delta",
"Echo",
"Foxtrot",
"Golf",
"Hotel",
"India",
"Juliet",
"Kilo",
"Lima",
"Mike",
"November",
"Oscar",
"Papa",
"Quebec",
"Romeo",
"Sierra",
"Tango",
"Uniform",
"Victor",
"Whiskey",
"Xray",
"Yankee",
"Zulu",
NULL
};

 void strtoupper(char *s)
 {
   while (*s)
   {
     if ((*s >= 'a') && (*s <= 'z'))
          *s -= ('a'-'A');
     s++;
   }
 }

 char * findMatch(char *table[], char c) 
 {
   int i;
   for(i=0; table[i] != NULL; i++)
   {
       if ( table[i][0] == c) // if first character matches
       {
         return table[i];
       }
   }   

   return NULL;
 }

 int printConvertedText(char *input)
 {
 int i;

 strtoupper(input);   // convert all letters to caps   

 for (i=0;input[i]!=0;i++)
 {
   // take characters from the input string 
    char c = input[i];
   // and find matching first letter in the alphaTable 
    char * result = findMatch(alphaTable,c);
    if(result)
    {
        printf(" %s",result);
    }
    else // NOT A LETTER 
    {
        if (isdigit(c)) // number 
        {
            int num = c-'0'; // a short cut: get a number   
            int j;

             printf(" "); 

            for(j=0;j<num;j++) // nothing printed for 0!
            {
             printf("%s","*");     
            }
        }
        else // everything else is printed as is
        {
             printf("%c",c);                   
        }    
    }
 }

 return 0;
}

int main()
{
  size_t bytes_read  = 0;
  size_t nbytes      = 1000;
  char *my_string;

  // this works for given string: 
  // char input [] = "Hello 2 you!."; 
  // printConvertedText(input);

  puts ("Please enter a line of text: ");
  my_string = (char *) malloc (nbytes + 1); // alocate memory for input

  bytes_read = getline (&my_string, &nbytes, stdin); // get the input

  if (bytes_read == -1)
  {
    puts ("ERROR!\n");
  }
  else
  {
    puts ("You typed:");
    puts (my_string);

    puts ("After conversion:");
    printConvertedText(my_string);

  }

  return 0;
}

//输出：

Please enter a line of text:                                                                                                                                                                                                                                                                                    
hello2 you!!.                                                                                                                                                                                                                                                                                                   
You typed:                           
hello2 you!!.

After conversion:                                                                                                                                                                                                                                                                                     
 Hotel Echo Lima Lima Oscar **  Yankee Oscar Uniform!!.

您可以运行代码here

将单词分成字母并用其他字母替换字母

1 个答案: