我使用HTML,Javascript和bootstrap来构建一个Web应用程序并且已经碰壁了,我尝试使用$(document).ready(function(){
$("button").click(function(){
var word = document.getElementById("sbar");
$.ajax({
url: 'https://community-food2fork.p.mashape.com/search?key=0ee5a01caf7f7c3512b54978628f1a4e&q=' + word, // The URL to the API. You can get this in the API page of the API you intend to consume
type: 'GET', // The HTTP Method, can be GET POST PUT DELETE etc
data: {}, // Additional parameters here
dataType: 'json',
success: function(data) {
search = JSON.parse(JSON.stringify(data.recipes));
console.dir(search);
},
error: function(err) {
alert(err);
},
beforeSend: function(xhr) {
xhr.setRequestHeader("X-Mashape-Authorization", "KEY HERE"); // Enter here your Mashape key
}
});
});
但是只返回了一个0的数组。我想从api中获取数据然后显示它在媒体列表上,我试图使用搜索栏作为过滤api GET的关键词的方式,因为我已经阅读过,这可以在api即时使用。
<div class="container">
<div style="background: rgba(60, 255, 60, 0.2);" class="jumbotron">
<h1>Meal Manager</h1>
<p class="lead">A simple recipe app that provides ingerdiants fast.</p>
<div class="input-group">
<input type="text" id="sbar" class="form-control" aria-label="...">
<div class="input-group-btn">
<button type="button" class="btn btn-default" id="button" title="Search Database">
<span class="glyphicon glyphicon-search" aria-hidden="true"></span>
</button>
<button type="button" class="btn btn-default btn" title="Sort by reviews" >
<span class="glyphicon glyphicon-star" aria-hidden="true"></span>
</button>
<button type="button" class="btn btn-default btn" title="Sort by trending" >
<span class="glyphicon glyphicon-hand-up" aria-hidden="true"></span>
</button>
</div>
</div>
输入的HTML:
for(int i = 0; i < pChain.Count(); i++)
{
// If the amount(Count) of SequenceEqual lists in pChain for the current iteration
// of pChain (pChain[i]) is > 1
if (pChain.Count(l => l.SequenceEqual(pChain[i])) > 1)
pChain.RemoveAt(i);
}
答案 0 :(得分:0)
你的代码几乎没问题。 HTML缺少一些div
结束以及你的JS。 (至少你在这里粘贴的片段)。
我已经构建了这个JSFiddle来测试它并且它有效。
只需改变:
url: 'https://…&q=' + word
为:
url: 'https://…&q=' + word.value
您的API调用有效并且它正在响应:
{&#34; message&#34;:&#34;无效的Mashape Key&#34;}
这完全是逻辑的,因为您需要替换真实密钥的"KEY HERE"
部分。查看Mashape Keys
xhr.setRequestHeader("X-Mashape-Authorization", "KEY HERE");