Question

我有一个选择字段＆＃39;州＆＃39;其值为$xpath = new DOMXPath($dom); $metas = $xpath->query('//meta[@property="al:ios:url"]'); $id = ""; if (preg_match('~[?&]id=(\d+)~', $metas->item(0)->getAttribute('content'), $match)) { $id = $match[1]; }。

我按照“州”字样对记录进行了分组。字段，但我们如何按字段值对记录进行分组，在本例中为resolved, dismissed, closed？

resolved, dismissed and closed

Answer 1

可以通过在过滤器中指定域来实现。

<filter string="Resolved" domain="[('state','=','resolved')]" />
<separator/>
<filter string="Dismissed" domain="[('state','=','dismissed')]" />
<separator/>
<filter string="Closed" domain="[('state','=','closed')]" />

一旦您选择了将根据您在域中指定的条件过滤结果集的过滤器，它将创建3个过滤器。

要为所有这三个生成group by，您需要通过为group by创建三个单独的过滤器来指定相同的域。

<group extend="0" string="Group By">
    <filter name="attachment_type" string="attachment Type" context="{'group_by' : 'attachment_type'}"></filter>
    <filter name="state_resolved" string="Resolved" context="{'group_by': 'state'}" domain="[('state','=','resolved')]" ></filter>
    <filter name="state_dismissed" string="Dismissed" context="{'group_by': 'state'}" domain="[('state','=','dismissed')]" ></filter>
    <filter name="state_closed" string="Closed" context="{'group_by': 'state'}" domain="[('state','=','closed')]" ></filter>
</group>

ODOO：按字段值分组

1 个答案: