Question

我想更新我的密码字段仅当输入时输入密码（非空），但同时“用户名”可以在表格中更新。

这是我目前的PHP代码：

UPDATE `my_tbl` 
SET `username`= '".$dataArray['username']."', `password` = IF( IS NULL('".$dataArray['password']."'),  
   `password`, '".$dataArray['password']."') 
WHERE `id` = ".$dataArray['id']

Answer 1

使用连接来解决此问题

$sql= UPDATE `my_tbl` SET `username`= '".$dataArray['username']."', 
                    `password` = IF( IS NULL('".$dataArray['password']."'),  `password`, '".$dataArray['password']."')
                    WHERE `id` = ".$dataArray['id'];

将此查询更改为

 $condition="";
    if($dataArray['password'] != ""){
       $condition=" , `password` = '".$dataArray['password']."'";
    }

     $sql= "UPDATE `my_tbl` SET `username`= '".$dataArray['username'] ."' ".$condition."
                        WHERE `id` = ".$dataArray['id'];
                        echo $sql;

Answer 2

if($dataArray['password'])       
{
$condition=" , `password` = '".$dataArray['password']."'";   }  else 
{    
$condition="";    
}    
$sql= "UPDATE `my_tbl` SET `username`= '".$dataArray['username'] ."' ".$condition."  WHERE `id` = ".$dataArray['id'];

Answer 3

使用codeigniter活动记录：

$data['username'] = $dataArray['username'];

if(!empty($dataArray['password'])) {
    $data['password'] = $dataArray['password'];
}

$this->db->where('id', $dataArray['id']);
$this->db->update('my_tbl',$data);

如果mySQL中提供的数据不为null，则更新字段

3 个答案: