Question

如何在drupal中编写SQL LIKE查询，

SELECT title FROM { node } WHERE type='%s'

我想添加LIKE CONDITION IN THAT

SELECT title FROM { node } WHERE type='%s' AND LIKE '%S%'

我认为我写错了像查询formnat，可以重写并告诉我，

Answer 1

只需使用％即可逃脱。

$result = db_query('SELECT title FROM {node} WHERE type = "%s" AND title LIKE "%%%s%%"', 'type', 'title');

while ($row = db_fetch_object($result)) {
     // do stuff with the data
}

节点类型不需要转义。

Answer 2

drupal_query将%%替换为％，将％s替换为值字符串

所以你的代码将是

$sql = "SELECT title FROM node WHERE type='%%%s' AND title LIKE '%%%S%%'";
$type = "type to use in query";
$title = "title to use in query";    
$result = db_result(db_query($sql, $type, $title));

Answer 3

好的，您希望LIKE运算符引用title列。使用此查询：

$sql = "SELECT title FROM node WHERE type='%s' AND title LIKE '%S%'";
$type = "type to use in query";
$title = "title to use in query";    
$result = db_result(db_query($sql, $type, $title));

这是因为LIKE运算符需要指定列名。否则，您的数据库不知道您要执行比较的值。请参阅here。

Answer 4

以下是如何在动态查询中使用LIKE的示例（ Drupal 7 Only ）：

$query = db_select('node', 'n')
        ->fields('n', array('title'))
        ->condition('type', 'my_type')
        ->condition('title', '%' . db_like(search_string) . '%', 'LIKE');
    $result = $query->execute()->fetchCol();

db_like()用于转义在LIKE模式中用作通配符的字符。

如何在drupal中使用类似的查询

4 个答案: