Question

我通过执行Php函数从我的html页面发送邮件，我的index.html：

  <form method="POST" action="sendmail.php" >
 <input type="text" name="sender_name" placeholder="Name" required="">
 <input type="text" name="sender_email" placeholder="Email" required="">
 <input type="text" name="subject" placeholder="Subject" required="">
 <textarea placeholder="Message" name="message" required=""></textarea>
  <input type="submit" name="send" value="SEND">

    </form>

我的sendmail.php：

<?php
if($_POST['send'] == 'SEND'){

$to      = 'queries@mydomain.com';
$subject = $_POST['subject']; 
$message = $_POST['message']; 
$headers = "From: ".$_POST['sender_nam‌e']." <".$_POST['sender_em‌ail‌'].">\r\n"; $headers = "Reply-To: ".$_POST['sender_ema‌il‌']."\r\n"; 
$headers = "Content-type: text/html; charset=iso-8859-1\r\n";
'X-Mailer: PHP/' . phpversion();
mail($to, $subject, $message, $headers);
}
?>

以上工作正常，但它也离开当前页面我想在当前页面上执行上述方法，并根据此question＆amp;这question

我必须使用 Ajax 和 jQuery ？到目前为止我对他们一无所知我有这个：

////in my index.html
<button type="button">send mail</button>
<p></p>
<script type="text/javascript">



    $(document).ready(function(){
        $("button").click(function(){

            $.ajax({
                type: 'POST',
                url: 'sendmail.php',
                success: function(data) {
                    alert(data)
                    $("l").text(data);

                }
            });
   });
});
</script>

我知道上面的不正确＆amp;它不工作（目前它在弹出窗口中显示sendmail.php的文本）我怎样才能使它工作，以便我可以执行sendmail.php ???

更新：

的index.html

    <form method="POST" id="myForm" action="sendmail.php">
  <input type="text" name="sender_name" placeholder="Name" required="">
  <input type="text" name="sender_email" placeholder="Email" required="">
  <input type="text" name="subject" placeholder="Subject" required="">
  <textarea placeholder="Message" name="message" required=""></textarea>
  <input type="submit" name="send" value="SEND">
</form>



</div>
<script type="text/javascript">


  $(document).ready(function(){
        $("#myForm").on('submit', function(){
            var formData = $(this).serialize();
            $.ajax({
                type: 'POST',
                url: 'sendmail.php',
                data: formData,
                success: function(response.success) {
                    alert(response.success)
                    $("l").text(response.success);

                }
            });
   });
</script>
    `

Answer 1

以下内容适用于.on('submit'和.serialize()

<强> HTML

<form method="POST" id="myForm" action="sendmail.php">
  <input type="text" name="sender_name" placeholder="Name" required="">
  <input type="text" name="sender_email" placeholder="Email" required="">
  <input type="text" name="subject" placeholder="Subject" required="">
  <textarea placeholder="Message" name="message" required=""></textarea>
  <input type="submit" name="send" value="SEND">
</form>

<强> JS

$(document).ready(function() {
    $("#myForm").on('submit', function(event) {
        event.preventDefault(); 
        var formData = $(this).serialize();
        $.ajax({
            type: 'POST',
            url: 'sendmail.php',
            dataType: "json",
            data: formData,
            success: function(response) { 
                alert(response.success); 
            },
            error: function(xhr, status, error){
                console.log(xhr); 
            }
        });
    });
});

<强> PHP

<?php
if(isset($_POST['message'])){
    $to      = 'queries@mydomain.com';
    $subject = $_POST['subject']; 
    $message = $_POST['message']; 
    $headers = "From: ".$_POST['sender_nam‌e']." <".$_POST['sender_em‌ail‌'].">\r\n"; $headers = "Reply-To: ".$_POST['sender_ema‌il‌']."\r\n"; 
    $headers = "Content-type: text/html; charset=iso-8859-1\r\n";
    'X-Mailer: PHP/' . phpversion();
    if(mail($to, $subject, $message, $headers)) echo json_encode(['success'=>true]); 
    else echo json_encode(['success'=>false]);
    exit;
 }
?>

Answer 2

  $(document).ready(function(){
        $("#my_button").click(function(){

            $.ajax({
                type: 'POST',
                url: 'sendmail.php',
                data : $('#my_form').serialize(),
                success: function(data) {

                }
            });
   });

jQuery代码

<?php

$searcharray = array();
parse_str($_POST['data'], $searcharray);
if($searcharray['send'] == 'SEND'){

$to      = 'queries@mydomain.com';
$subject = $searcharray['subject']; 
$message = $searcharray['message']; 
$headers = "From: ".$searcharray['sender_nam‌e']." <".$searcharray['sender_em‌ail‌'].">\r\n";
$headers .= "Reply-To: ".$searcharray['sender_ema‌il‌']."\r\n"; 
$headers .= "Content-type: text/html; charset=iso-8859-1\r\n";
$headers .= 'X-Mailer: PHP/' . phpversion();
mail($to, $subject, $message, $headers);
}

Php代码

class Person(models.Model):
    identity_number = models.CharField(max_length=20)
    identity_type = models.IntegerField()

class Student(Person):
    student_number = models.CharField(max_length=20)

class Employee(Person):
    employee_number = models.CharField(max_length=20)

Answer 3

请为您的表单标记提供id和id，如下面的代码。

 <form method="POST" action="sendmail.php" id="sendForm">
 <input type="text" name="sender_name" placeholder="Name" required="">
 <input type="text" name="sender_email" placeholder="Email" required="">
 <input type="text" name="subject" placeholder="Subject" required="">
 <textarea placeholder="Message" name="message" required="">  
 </textarea>
 <input type="submit" name="send" value="SEND" id="submitButton">    
 </form>

然后像下面的代码一样更新你的脚本

    $(document).ready(function(){
        $("#submitButton").click(function(event){
         event.preventDefault();
        var datas = $('#sendForm').serialize();

            $.ajax({
                type: 'POST',
                url: 'sendmail.php',
                data: datas,

                success: function(data) {
                    alert(data)
                    $("l").text(data);

                }
            });
   });
});

检查此documentation，了解如何使用ajax

提交表单数据

Answer 4

您的表单为id并使用JS preventDefault()

<form method="POST" id="myForm" action="sendmail.php">
  <input type="text" name="sender_name" placeholder="Name" required="">
  <input type="text" name="sender_email" placeholder="Email" required="">
  <input type="text" name="subject" placeholder="Subject" required="">
  <textarea placeholder="Message" name="message" required=""></textarea>
  <input type="submit" id="sendMail" name="send" value="SEND">
</form>

sendmail.php

<?php
    if($_POST['send'] == 'SEND'){

    $to      = 'queries@mydomain.com';
    $subject = $_POST['subject']; 
    $message = $_POST['message']; 
    $headers = "From: ".$_POST['sender_nam‌e']." <".$_POST['sender_em‌ail‌'].">\r\n"; $headers = "Reply-To: ".$_POST['sender_ema‌il‌']."\r\n"; 
    $headers = "Content-type: text/html; charset=iso-8859-1\r\n";
    'X-Mailer: PHP/' . phpversion();
    //check if the mail was sent
    if (mail($to, $subject, $message, $headers)) {
        echo json_encode(['result' => true]);
    }else {
        echo json_encode(['result' => false]);
     }
   }
?>

的jQuery

$(document).ready(function () {
//send button click
$('#sendMail').on('click', function (e) {
    e.preventDefault();
    $.post('sendmail.php', $('#myForm').serialize(), function (data) {
        //show the results if the mail was sent or not
        var res = $.parseJSON(data);
        if (res.result === true) {
           $('#feedback').html('your mail was sent');
        }else {
           $('#feedback').html('your mail was not sent');
        }
    });
});
});

使用Ajax和jQuery发送邮件（邮件到php Post方法）

4 个答案: