我有以下SQL查询,正如我们在屏幕截图中看到的,有两个重复行具有相同的constr_id
(2015)值但具有不同的assigned_insurance_packages
。
查询:
select
ac.constr_id,
AIP.NAME as ASSIGNED_INSURANCE_PACKAGES,
ac.code,ac.constr_name,
ac.offer_name,
ac.repay_freq,
ac.min_amt,
ac.max_amt,
ac.min_downpay_percent,
ac.max_downpay_percent,
ac.downpay_amount,
ac.min_term,
(select
listagg(AF.NAME, '; ') within group(order by ACF.CONSTR_ID)
from
CREDILOGIC.ACQ_CONSTR_FEE acf, CREDILOGIC.ACQ_FEE af
where
ACF.CONSTR_ID = AC.CONSTR_ID and AF.FEE_ID = ACF.FEE_ID) as CONSTRUCTION_FEES,
INS_COMPANY.SHORT_NAME,
(select listagg(x.DURATION_MIN || '-' || TO_CHAR(x.RATE_SHIFT, '90.99') || ',' || x.DURATION_MAX || '-' || TO_CHAR(x.RATE_SHIFT, '90.99'), '; ') within group (order by X.CONSTRUCTION_ID)
from credilogic.ACQ_CONSTRUCTION_BASERATE x
where X.CONSTRUCTION_ID = AC.CONSTR_ID) as RATE
from
CREDILOGIC.ACQ_CONSTRUCTION ac
left join
CREDILOGIC.ACQ_CONSTR_INSPACKAGE aci on ACI.CONSTR_ID = AC.CONSTR_ID
and ACI.DELETED_TSTAMP is null
left join
CREDILOGIC.ACQ_INSURANCE_PACKAGE aip on AIP.INSURANCE_PACKAGE_ID = ACI.INSURANCE_PACKAGE_ID
left join
credilogic.ath_party ins_company ON INS_COMPANY.PARTY_ID = aip.PARTY_ID
left join
credilogic.ACQ_CONSTRUCTION_DUEDATE acd on ac.constr_id = acd.constr_id
left join
credilogic.ACQ_APPLICATION acp on ac.constr_id = acp.construction_id
我将创建另外两个列,例如0.3% insurance pack
和0.5% insurance pack
,将ASSIGNED_INSURANCE_PACKAGES
值放入不同的列,如下图所示