Question

我简要解释问题。

select distinct  DATE from #Table where   DATE >='2016-01-01'

输出：

Date 
2016-11-23  
2016-11-22  
2016-11-21  
2016-11-19  
2016-11-18

现在我需要找出缺少的日期与我们的年度＆＃39; 2016＆＃39;

的日历比较

即。这里约会＆＃39; 2016-11-20 ＆＃39;不见了。

我想要缺少日期列表。

感谢您阅读本文。祝你有美好的一天。

Answer 1

你需要生成日期，你必须找到遗漏的日期。下面用递归cte我已经完成了

  ;WITH CTE AS
    (
    SELECT CONVERT(DATE,'2016-01-01') AS DATE1
    UNION ALL
    SELECT DATEADD(DD,1,DATE1) FROM CTE WHERE DATE1<'2016-12-31'
    )
    SELECT DATE1 MISSING_ONE FROM CTE
    EXCEPT 
    SELECT * FROM #TABLE1
    option(maxrecursion 0)

Answer 2

您需要生成日期，然后找到遗漏的日期。递归CTE是生成少数日期的一种方法。另一种方法是使用master..spt_values作为数字列表：

with n as (
      select row_number() over (order by (select null)) - 1 as n
      from master..spt_values
     ),
     d as (
      select dateadd(day, n.n, cast('2016-01-01' as date)) as dte
      from n
      where n <= 365
     )
select d.date
from d left join
     #table t
     on d.dte = t.date
where t.date is null;

如果您对缺少日期的范围感到满意，则根本不需要日期列表：

select date, (datediff(day, date, next_date) - 1) as num_missing
from (select t.*, lead(t.date) over (order by t.date) as next_date
      from #table t
      where t.date >= '2016-01-01'
     ) t
where next_date <> dateadd(day, 1, date);

Answer 3

使用CTE并获取CTE表中的所有日期，然后与您的表格进行比较。

CREATE TABLE #yourTable(_Values DATE)
INSERT INTO #yourTable(_Values)
SELECT '2016-11-23' UNION ALL 
SELECT '2016-11-22' UNION ALL  
SELECT '2016-11-21' UNION ALL
SELECT '2016-11-19' UNION ALL  
SELECT '2016-11-18'   


DECLARE @DATE DATE = '2016-11-01'
;WITH CTEYear (_Date) AS
(
  SELECT @DATE
  UNION ALL
  SELECT DATEADD(DAY,1,_Date)
  FROM CTEYear
  WHERE _Date < EOMONTH(@DATE,0)
)

SELECT * FROM CTEYear
WHERE NOT EXISTS(SELECT 1 FROM #yourTable WHERE _Date = _Values)
OPTION(maxrecursion 0)

查找与日历比较的缺失日期

3 个答案: