返回shell

Question

我在.bash_profile

中有这个功能

function suman {
       LOCAL_SUMAN=$(node $HOME/.suman/find-local-suman-executable.js);

       if [ -z "$LOCAL_SUMAN" ]; then
           echo "No local Suman executable could be found, given the current directory => $PWD"
           return 1;
       else
           return node "$LOCAL_SUMAN" "$@";  # this is wrong I think
       fi

  } 

我只想返回节点进程的退出代码，但我认为上面的行不正确，从suman函数返回正确退出代码的正确方法是什么？

我猜想退出代码会被同一行上的节点进程“返回”。

也许我应该删除return关键字？

Answer 1

在该行中您不需要node "$LOCAL_SUMAN" "$@";只需致电node;由于它是您的函数执行的最后一个命令，因此您的函数将以与调用suman () { LOCAL_SUMAN=$(node $HOME/.suman/find-local-suman-executable.js) if [ -z "$LOCAL_SUMAN" ]; then echo "No local Suman executable could be found, given the current directory => $PWD" return 1 else node "$LOCAL_SUMAN" "$@" fi } 相同的返回状态退出。

List<T> oldList = new List<T> { Soc1, Soc2, Soc3 };
List<T> newList = new List<T> { Soc1, Soc3, Soc4 };

int i = 0;
// Go trough the old list to remove items which don't exist anymore
while(i < oldList.Count)
{
    // If the new list doesn't contain the old element, remove it from the old list
    if (!newList.Contains(oldList[i]))
    {
        oldList.RemoveAt(i);
    }
    // Otherwise move on
    else
    {
        i++;
    }
}

// Now go trough the new list and add all elements to the old list which are new
foreach(T k in newList)
{
    if (!oldList.Contains(k))
    {
        oldList.Add(k);
    }
}