Question

我最近创建了一个名为Movie_Stars的表。它包含6列：Movie_Number编号唯一，Movie_Title varchar2（30）唯一，Year_Released日期不为null，First_Name varchar2（15），Last_Name varchar2（15）和Movie_Category varchar2（15）。我需要在表中插入以下值：

insert all
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)
          values (1, 'New York Stories', 'January 1 1984', Nick, Nolte, Drama)
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)      
          values (2, 'Speed', '1999, FEB 12', Keanu, Reeves, Action)
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)
          values (3, 'Superman', '1982, MAR 7', Chris, Reeve, Action)
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)
          values (4, 'Ice Age', '2002, April 2', Chris, Rock, Cartoon)
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)
          values (5, 'Bowfinger', '2001, August 03', Eddie, Murphy, Comedy);
select * from dual;

但是，当我运行代码时，它返回了以下结果：

DUMMY
-----
1 x

这是什么意思，我该如何解决？

Answer 1

INSERT ALL和SELECT之间有一个错误的分号;这意味着它们是两个不同的陈述，而不是一个陈述。
您缺少很多用于包装字符串值的引号
您不能以这种方式插入日期值;您必须使用to_date或使用ANSI标准

您可以将代码重写为：

insert all
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)
          values (1, 'New York Stories', date '1984-01-01', 'Nick', 'Nolte', 'Drama')
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)      
          values (2, 'Speed', date '1992-02-12', 'Keanu', 'Reeves', 'Action')
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)
          values (3, 'Superman', date '1982-03-07', 'Chris', 'Reeve', 'Action')
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)
          values (4, 'Ice Age', to_date ('02/04/2002', 'dd/mm/yyyy'), 'Chris', 'Rock', 'Cartoon')
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)
          values (5, 'Bowfinger', date '2001-08-03', 'Eddie', 'Murphy', 'Comedy')
select * from dual;

插入多行时的虚拟结果

1 个答案: