Question

import random


def diceroll():
        num_dice = random.randint(1,6)
        print("You got " + str(num_dice) + "!")
diceroll()
def question():
    response = input("You want to roll again?\n")
        while response == "y":
        diceroll()
        response = input("You want to roll again?\n")   
    if response == "n":
        print("Thank you for playing! :) ")
        exit()
    while "y" or "n" not in response:
            response = input("Please answer with y or n!\n")
            while response == "y":
                diceroll()
                response = input("You want to roll again?\n")   
            if response == "n":
                print("Thank you for playing! :) ")
                exit()
question()

有什么办法可以让这段代码变得更简单并具有相同的功能吗？我尝试了另一个版本而不使用类但是一旦我输入另一个字符，除了“y”或“n”代码结束。

import random

answer = "yes"

while answer in ["yes", "y"]:
    roll = random.randint(1,6)
    print("You rolled " + str(roll) + "!")
    answer = input("Would you like to roll again?\n")
if answer in ["n", "no"]:
    print("Thank you for playing!")
else :
    print("Please answer with yes or no!")
    answer = input("Would you like to roll again?\n")

Answer 1

除了＆＃34; y＆＃34;之后输入任何内容后程序退出的原因或＆＃34;是＆＃34;是因为你所采取的是留在循环中的条件。你的程序假设＆＃34;留在循环中＃34;意味着＆＃34;玩游戏＆＃34;，但当有人输入非法输入时，他们也应该留在循环中。退出的唯一原因是明确要求它，通过回答＆＃34; n＆＃34;或＆＃34;不＆＃34;。

因此：

import random

while answer not in ["no", "n"]:
    roll = random.randint(1, 6)
    print("You rolled " + str(roll) + "!")
    answer = input("Would you like to roll again?\n")
    if answer not in ["yes", "y", "no", "n"]:
        print("Please answer with yes or no!")
        answer = input("Would you like to roll again?\n")

print("Thank you for playing!")

我的第一次掷骰子蟒蛇游戏

1 个答案: