Question

我遇到以下问题（我在macOS上）： 12个USB闪存驱动器安装在/ Volumes中，它们的名称从cam0到cam11。每个驱动器都具有以下结构：cam0 / DCIM / 100HDDVR / C00_0001.mp4，cam1 / DCIM / 100HDDVR / C01_0001.mp4等。在每个100HDDVR文件夹中将有多个文件，因此对于cam0，例如它将是：C00_0001。 mp4，C00_0002.mp4，C00_0003.mp4等现在我想把它复制到桌面上，比方说，创建一个新的文件夹叫做：录制[添加今天日期]然后创建一个子文件夹shoot1，它将包含文件C00_0001.mp4到C11_0001.mp4并创建子文件夹shoot2将包含C00_0002.mp4到C11_0002.mp4，依此类推，直到复制闪存驱动器中的所有文件。

到目前为止，我设法将所有文件从cam0 / DCIM / 100HDDVR复制到新的文件夹录音/ cam0，但它不够自动化，我正在努力更新它。

def copyy(self):
        root.update_idletasks()
        self.status['text'] = "Files are being copyied, have patience ;)".format(self.status)


        self.source_direcotry0= '/Volumes/CAM0/DCIM/100HDDVR'
        self.source_direcotry1= '/Volumes/CAM1/DCIM/100HDDVR'
        self.source_direcotry2= '/Volumes/CAM2/DCIM/100HDDVR'
        self.source_direcotry3= '/Volumes/CAM3/DCIM/100HDDVR'
        self.source_direcotry4= '/Volumes/CAM4/DCIM/100HDDVR'
        self.source_direcotry5= '/Volumes/CAM5/DCIM/100HDDVR'
        self.source_direcotry6= '/Volumes/CAM6/DCIM/100HDDVR'
        self.source_direcotry7= '/Volumes/CAM7/DCIM/100HDDVR'
        self.source_direcotry8= '/Volumes/CAM8/DCIM/100HDDVR'
        self.source_direcotry9= '/Volumes/CAM9/DCIM/100HDDVR'
        self.source_direcotry10= '/Volumes/CAM10/DCIM/100HDDVR'
        self.source_direcotry11= '/Volumes/CAM11/DCIM/100HDDVR'

        self.path0="recording/CAM0"
        self.path1="recording/CAM1"
        self.path2="recording/CAM2"
        self.path3="recording/CAM3"
        self.path4="recording/CAM4"
        self.path5="recording/CAM5"
        self.path6="recording/CAM6"
        self.path7="recording/CAM7"
        self.path8="recording/CAM8"
        self.path9="recording/CAM9"
        self.path10="recording/CAM10"
        self.path11="recording/CAM11"


        self.cam0=os.path.join(self.Destination.get(), self.path0)
        self.cam1=os.path.join(self.Destination.get(), self.path1)
        self.cam2=os.path.join(self.Destination.get(), self.path2)
        self.cam3=os.path.join(self.Destination.get(), self.path3)
        self.cam4=os.path.join(self.Destination.get(), self.path4)
        self.cam5=os.path.join(self.Destination.get(), self.path5)
        self.cam6=os.path.join(self.Destination.get(), self.path6)
        self.cam7=os.path.join(self.Destination.get(), self.path7)
        self.cam8=os.path.join(self.Destination.get(), self.path8)
        self.cam9=os.path.join(self.Destination.get(), self.path9)
        self.cam10=os.path.join(self.Destination.get(), self.path10)
        self.cam11=os.path.join(self.Destination.get(), self.path11)

        self.p.start(1)


        self.work_thread = threading.Thread(target=self.copyy2, args=())
        self.work_thread.start()
        self.work_thread.join()


        self.p.stop()

        self.status['text'] = "Files have been copyied".format(self.status)

    def copyy2(self):

        shutil.copytree(self.source_direcotry0, self.cam0)
        shutil.copytree(self.source_direcotry1, self.cam1)
        shutil.copytree(self.source_direcotry2, self.cam2)
        shutil.copytree(self.source_direcotry3, self.cam3)
        shutil.copytree(self.source_direcotry4, self.cam4)
        shutil.copytree(self.source_direcotry5, self.cam5)
        shutil.copytree(self.source_direcotry6, self.cam6)
        shutil.copytree(self.source_direcotry7, self.cam7)
        shutil.copytree(self.source_direcotry8, self.cam8)
        shutil.copytree(self.source_direcotry9, self.cam9)
        shutil.copytree(self.source_direcotry10, self.cam10)
        shutil.copytree(self.source_direcotry11, self.cam11)

除此之外，你将如何处理这个问题，因此它也适用于Windows，当安装闪存驱动器时，你看不到它们的名字和磁盘字母总是不同。这甚至可能吗？

我希望我能够清楚地描述它，并提前感谢任何提示。

Answer 1

我会采取另一种方式：

获取/ Volume
搜索您想要的扩展名完成的所有文件：[0001.mp4,0002.mp4等..]
将这些文件复制到桌面上的子目录中。

对于（1）你可以使用：

def get_filepaths(directory, extension=None):
    """
    Generate the file names in a directory
    tree by walking the tree either top-down or bottom-up. For each
    directory in the tree rooted at directory top (including top itself),
    it yields a 3-tuple (dirpath, dirnames, filenames).
    """
    import os, ntpath
    assert(os.path.isdir(directory)), "The 'directory' parameter is not a directory (%s)"%(directory)

    file_paths = []  # List which will store all of the full filepaths.
    # Walk the tree.
    for root, directories, files in os.walk(directory):
        for filename in files:
            # Join the two strings in order to form the full filepath.
            filepath = os.path.join(root, filename)

            if not ntpath.basename(filepath).startswith("."):
                file_paths.append(filepath)  # Add it to the list.

    if extension:return [x for  x in file_paths if x.endswith(extension) ]

    return file_paths  # Self-explanatory

对于（2）和（3），你可以在循环中使用相同的功能：

# this is a pseudo code - no tested and has to be customized 
nb_shoot = n
for shoot_n in range(nb_shoot):
    # 1) looking for files to copy
    nb_zeros  = 3 - len(str(shoot_n)) # calculating the number of 0 to put in front of the filename
    zeros     = "0"*nb_zeros
    extension = "%s%shoot_n.mp4"%(zeros, shoot_n)
    paths_for_the_shoot = get_filepaths("/Volumes/", extension)
    #2) creating a new dir
    current_date = time.time()
    new_dir_name = "recording_%s/shoot_%s"%(current_date , shoot_n )
    os.mkdir(new_dir_name)
    for path in paths_for_the_shoot:
        #copy file
        os.copy(path, new_dir_name)

使用python将具有特定名称的文件复制到特定文件夹

1 个答案: