Question

我尝试使用临时表作为SELECT语句的中间结果持有者。问题是虽然我无法在其他查询语句中多次访问临时表，我希望这可能会使临时表无效。

MySql中是否有替代临时表，允许我提取我的SQL语句。

我无法使用存储过程（无法从公司使用的Web框架版本访问它们）而且我不想使用游标。

编辑：

我的代码看起来有点像这样：

创建临时表：

CREATE TEMPORARY TABLE dates_with_entries (
  seq  INT NOT NULL AUTO_INCREMENT PRIMARY KEY,
  datum VARCHAR(32)
);

INSERT INTO dates_with_entries (datum) SELECT datum AS Datum from project_times
    WHERE user_id = 20 GROUP BY datum ORDER BY datum desc LIMIT 13;

然后我使用临时表的代码看起来有点像这样（我把它简化为我遇到的问题......）

SELECT 
...
FROM (SELECT entrie_date AS datum FROM dates_with_entries ) AS sub_result
INNER JOIN project_times
    ON sub_result.datum = project_times.datum AND project_times.user_id = 20
LEFT JOIN works AS w ON project_times.work_id = w.id
LEFT JOIN sub_projects AS sp ON sp.id = w.sub_project_id
LEFT JOIN projects AS p ON p.id = sp.project_id
GROUP BY datum
UNION(
    SELECT
      ..
  FROM (SELECT entrie_date AS datum FROM dates_with_entries ) AS sub_result
  INNER JOIN project_times AS pt ON pt.datum = sub_result.datum
  INNER JOIN works AS w on w.id = pt.work_id
  INNER JOIN sub_projects AS sp on w.sub_project_id = sp.id
  INNER JOIN projects AS p ON sp.project_id = p.id
  WHERE pt.user_id = 20
);

这些数字稍后将被ruby替换，这仅用于测试SQL语句。

Answer 1

解决这个问题的一种方法是简单地创建一个“真实”表，而不是临时表。

临时表提供的优势：

的命名空间即可。您可以创建多个具有相同名称的临时表在单独的会议中。
自动清理。完成后，您不需要显式删除表它。当你结束会话时它会消失

如果＃1对您至关重要，那么您可能需要坚持使用临时表。否则，如果一次只运行此程序的一个实例，或者您动态创建表名以使其唯一，我建议您为此表选择一个适当的唯一名称并将其创建为“真实”表，然后你完成后放弃它。

Answer 2

已知错误（功能） - 阅读http://dev.mysql.com/doc/refman/5.0/en/temporary-table-problems.html

以下是我解决问题的方法......

drop table if exists employees;
create table employees
(
emp_id smallint unsigned not null auto_increment primary key,
name varchar(255) not null,
boss_id smallint unsigned null,
key (boss_id)
)
engine = innodb;

insert into employees (name, boss_id) values
('f00',null), 
  ('ali later',1), 
  ('megan fox',1), 
      ('jessica alba',3), 
      ('eva longoria',3), 
         ('keira knightley',5), 
            ('liv tyler',6), 
            ('sophie marceau',6);


drop procedure if exists employees_hier;

delimiter #

create procedure employees_hier
(
in p_emp_id smallint unsigned
)
begin

declare v_done tinyint unsigned default(0);
declare v_dpth smallint unsigned default(0);

create temporary table hier(
 boss_id smallint unsigned, 
 emp_id smallint unsigned, 
 depth smallint unsigned
)engine = memory;

insert into hier select boss_id, emp_id, v_dpth from employees where emp_id = p_emp_id;

/* http://dev.mysql.com/doc/refman/5.0/en/temporary-table-problems.html */

create temporary table emps engine=memory select * from hier;

while not v_done do

    if exists( select 1 from employees e inner join hier on e.boss_id = hier.emp_id and hier.depth = v_dpth) then

        insert into hier select e.boss_id, e.emp_id, v_dpth + 1 
            from employees e inner join emps on e.boss_id = emps.emp_id and emps.depth = v_dpth;

        set v_dpth = v_dpth + 1;            

        truncate table emps;
        insert into emps select * from hier where depth = v_dpth;

    else
        set v_done = 1;
    end if;

end while;

select 
 e.emp_id,
 e.name as emp_name,
 p.emp_id as boss_emp_id,
 p.name as boss_name,
 hier.depth
from 
 hier
inner join employees e on hier.emp_id = e.emp_id
left outer join employees p on hier.boss_id = p.emp_id;

drop temporary table if exists hier;
drop temporary table if exists emps;

end #

delimiter ;

-- call this sproc from your php

call employees_hier(1);

Answer 3

对于这个问题，只读取临时表，我创建第二个临时表作为第一个临时表的副本，然后在查询中使用它：

CREATE TEMPORARY TABLE t2 as (SELECT * FROM dates_with_entries);

然后

SELECT 
...
FROM (SELECT entrie_date AS datum FROM dates_with_entries ) AS sub_result
INNER JOIN project_times
    ON sub_result.datum = project_times.datum AND project_times.user_id = 20
LEFT JOIN works AS w ON project_times.work_id = w.id
LEFT JOIN sub_projects AS sp ON sp.id = w.sub_project_id
LEFT JOIN projects AS p ON p.id = sp.project_id
GROUP BY datum
UNION(
    SELECT
      ..
  FROM (SELECT entrie_date AS datum FROM t2) AS sub_result
  INNER JOIN project_times AS pt ON pt.datum = sub_result.datum
  INNER JOIN works AS w on w.id = pt.work_id
  INNER JOIN sub_projects AS sp on w.sub_project_id = sp.id
  INNER JOIN projects AS p ON sp.project_id = p.id
  WHERE pt.user_id = 20
);

Answer 4

我为这个问题尝试了“ WITH”，但是显然我的服务器上的MySQL还不支持它。我遇到了似乎可行的解决方案。它使用“ CREATE VIEW”在MySQL中复制“ WITH”

http://guilhembichot.blogspot.com/2013/11/with-recursive-and-mysql.html

在MySql中多次访问临时表

4 个答案: