任何人都可以帮我重建以下MySQL查询,以便它可以工作:
git fetch
该查询应该统计来自两个来源的所有不同学生,并按合同对其进行分组。
问题是对c.id的子查询引用。很明显,子查询对合同表一无所知。
我非常感谢帮助它发挥作用。
谢谢!
答案 0 :(得分:1)
您需要在子查询中选择cs2.contract
,然后在外部查询中将其与c.id
连接。
SELECT c.id, COUNT(d.student_id)
FROM contract c
JOIN (
SELECT cs2.contract, student_id
FROM ilc_course ic
JOIN contract_seat cs2 ON cs2.id = ic.contract_seat
WHERE ic.valid = 1 AND cs2.valid = 1
AND (ic.finished IS NULL OR ic.finished > CURRENT_TIMESTAMP)
UNION
SELECT cs2.contract, student_id
FROM glc_to_user_profile_student gtups
JOIN glc_course gc ON gtups.glc_course = gc.id
JOIN contract_seat cs2 ON gtups.contract_seat = cs2.id
WHERE gtups.valid = 1 AND gc.valid = 1 AND cs2.valid = 1
AND (gtups.left_date IS NULL OR gtups.left_date > CURRENT_TIMESTAMP)
AND (gc.end_date IS NULL OR gc.end_date > CURRENT_TIMESTAMP)
) d ON c.id = d.contract
GROUP BY c.id;
此外,由于UNION
会从子查询中删除重复项,因此您无需在DISTINCT
中使用COUNT()
。