Question

我是PHP的新手。我有一个有三个用户的虚拟数据库，我想将他们的键和值插入一个数组。

$result_set=$database->GeneralQuery("SELECT * FROM users");
$the_object_array=array();
while ($row=mysqli_fetch_assoc($result_set)) {
   foreach($row as $key => $value){
      $the_object_array[$key] = $value;             
   }
}
print_r($the_object_array);

返回： -

Array ( [id] => 3 [username] => anne [password] => 123 [first_name] => Anne [last_name] => Baird ).....

换句话说，只有数据库表中的最后一个用户带有键和值。

如何让print_r($the_object_array)使用键和值打印出所有三个用户

Answer 1

尝试以下代码

$result_set=$database->GeneralQuery("SELECT * FROM users");
$the_object_array=array();
while ($row = mysqli_fetch_assoc($result_set)) { 
   $the_object_array[] = $row; 
} 
print_r($the_object_array);

Answer 2

尝试这样的事情......

您已删除foreach中的密钥...就像这样$the_object_array[] = $value1;

$the_object_array=array();
    $row = array(
            '1'=>array(
                'id' =>'3',
                'name'=>'test'
            ),
            '2'=>array(
                'id' =>'3' ,
                'name'=>'test1'
            )
        );
    foreach($row as $key => $value){
        foreach ($value as $key1 => $value1) {
            $the_object_array[] = $value1;
        }
    }
    print_r($the_object_array);

从foreach循环返回

2 个答案: