Question

这样的数组

$arr = array(
'slidelink' => 'presentation.pptx',
'productid' => array(1,3),
'order' => 2,
'class_id' => array(1,2),
'currency_id' => array(1,2),
'presentation_type' => 1,
'distribution' => 0,

）;

我希望将它的所有可能输出生成到一个新数组，所以在这种情况下有8行像：

$new_arr = array (
 0 => array(presentation.pptx, 1, 2, 1, 1, 1, 0),
 1 => array(presentation.pptx, 1, 2, 1, 2, 1, 0),
 2 => array(presentation.pptx, 1, 2, 2, 1, 1, 0),
 3 => array(presentation.pptx, 1, 2, 2, 2, 1, 0),
 4 => array(presentation.pptx, 3, 2, 1, 1, 1, 0),
 5 => array(presentation.pptx, 3, 2, 1, 2, 1, 0),
 6 => array(presentation.pptx, 3, 2, 2, 1, 1, 0),
 7 => array(presentation.pptx, 3, 2, 2, 2, 1, 0)
);

我该怎么做？

谢谢！

Answer 1

实际上，您的问题是更具体的情况（未存储数组键），但这是通用的方法：

$arr = [
    'size'  => [ 'XS', 'S', 'M', 'L', 'XL', 'XXL' ],
    'color' => [ 'yellow', 'brown', 'white' ],
    'weight'=> [ 'super', 'normal' => [ 'extra', 'high' => [ 'super', 'low' => 'lower' ] ], 'extra' , 'medium', 'heavy', 'overload' ]
];


function variations( $array ){

    if( empty( $array ) ) return [];

    function traverse( $array, $parent_ind ){
        $r = [];
        $pr = '';
        if( !is_numeric($parent_ind) )
            $pr = $parent_ind . '-';
        foreach( $array as $ind=>$el ) {
            if ( is_array( $el ) ) {
                $r = array_merge( $r, traverse( $el, $pr . ( is_numeric( $ind ) ? '' : $ind ) ) );
            }else
                if ( is_numeric( $ind ) )
                    $r[] = $pr . $el;
                else
                    $r[] = $pr . $ind . '-' . $el;
        }
        return $r;
    }

    //1. Go through entire array and transform elements that are arrays into elements, collect keys
    $keys = [];$size = 1;
    foreach( $array as $key=>$elems ) {
        if ( is_array( $elems ) ) {
            $rr = [];
            foreach ( $elems as $ind=>$elem ) {
                if ( is_array( $elem ) )
                    $rr = array_merge( $rr, traverse( $elem, $ind ) );
                else $rr[] = $elem;
            }
            $array[ $key ] = $rr;
            $size *= count( $rr );
        }
        $keys[] = $key;
    }

    //2. Go through all new elems and make variations
    $rez = [];
    for( $i = 0; $i < $size; $i++ ) {
        $rez[ $i ] = array();
        foreach( $array as $key => $value ){
            $current = current( $array[ $key ] );
            $rez[ $i ][ $key ] = $current;
        }
        foreach( $keys as $key )
            if( !next( $array[ $key ] ) ) reset( $array[ $key ] );
            else break;
    }

    return $rez;

}


die( print_r( variations( $arr ) ) );

结果将：

Answer 2

对所有子数组的数组元素使用嵌套循环。

要处理元素可能不是数组的可能性，可以使用强制转换将其转换为数组。

$new_arr = array();
foreach ((array)$arr['slidelink'] as $s) {
    foreach ((array)$arr['productid'] as $pid) {
        foreach ((array)$arr['order'] as $o) {
            foreach ((array)$arr['class_id'] as $cid) {
                foreach ((array)$arr['currency_id'] as $curr) {
                    foreach ((array)$arr['presentation_type'] as $p) {
                        foreach ((array)$arr['distribution'] as $d) {
                            $new_arr[] = array($s, $pid, $o, $cid, $curr, $p, $d);
                        }
                    }
                }
            }
        }
    }
}

从阵列生成所有可能的变体

2 个答案: