Question

我正在编写一个需要提取7z档案的Android应用程序。按时间，我正在搜索可以在我的项目中使用的第三方库或源代码。

我将.so文件复制到/ libs文件夹

应用\ SRC \主\ jniLibs \ armeabi \ libun7z.so

我无法在android

中提取7z文件

AndUn7z.extract7z（My7z，My7zPath）;

运行此行后

我有这个错误：

java.lang.UnsatisfiedLinkError中：未找到对于int com.darkgamers.pepsiman.browser.mainmenu.AndUn7z.un7zip（java.lang.String中，java.lang.String中）执行（试图Java_com_darkgamers_pepsiman_browser_mainmenu_AndUn7z_un7zip和Java_com_darkgamers_pepsiman_browser_mainmenu_AndUn7z_un7zip__Ljava_lang_String_2Ljava_lang_String_2）在com.darkgamers.pepsiman.browser.mainmenu.AndUn7z.un7zip（原生方法）

这是我的代码：

public class AndUn7z {

public static boolean extract7z(String filePath, String outPath)
{
    File outDir = new File(outPath);
    if(!outDir.exists() || !outDir.isDirectory())
    {
        outDir.mkdirs();
    }
    return (AndUn7z.un7zip(filePath, outPath) == 1);
}

/**
 * Extract from assets
 * @param context
 * @param assetPath
 * @param outPath
 * @return
 * @throws Exception
 */
public static boolean extractAssets(Context context, String assetPath, String outPath)
{
    File outDir = new File(outPath);
    if(!outDir.exists() || !outDir.isDirectory())
    {
        outDir.mkdirs();
    }

    String tempPath = outPath + File.separator + ".temp";
    try {
        copyFromAssets(context, assetPath, tempPath);
    } catch (Exception e) {
        e.printStackTrace();
        return false;
    }
    boolean ret = (AndUn7z.un7zip(tempPath, outPath) == 1);
    new File(tempPath).delete();

    return ret;
}

/**
 * Copy asset to temp
 * @param context
 * @param assetPath
 * @param tempPath
 * @throws Exception
 */
private static void copyFromAssets(Context context, String assetPath, String tempPath)
        throws Exception
{
    InputStream inputStream = context.getAssets().open(assetPath);
    FileOutputStream fileOutputStream = new FileOutputStream(tempPath);
    int length = -1;
    byte[] buffer = new byte[0x400000];
    while ((length = inputStream.read(buffer)) != -1) {
        fileOutputStream.write(buffer, 0, length);
    }
    fileOutputStream.flush();
    fileOutputStream.close();
    inputStream.close();
}

//JNI interface
private static native int un7zip(String filePath, String outPath);

static {
    System.loadLibrary("un7z");
}

}

Answer 1

下载7z SDK for Java并按以下方式重复使用其"<"类：

LzmaAlone

Answer 2

使用7z筹集资金并知道您要7z之后，在xz中使用Java API会容易得多：

XZInputStream in = new XZInputStream(your_input_stream_xz_compressed);
FileOutputStream out = new FileOutputStream(your_output_file_decompressed);
byte[] buffer = new byte[1024];
int length;

while ((length = in.read(buffer)) != -1) // Copy DB byte for bite
  out.write(buffer, 0, length);

out.flush();
out.close();
in.close();

如何提取7z文件android studio

2 个答案: