Question

enter image description here

我创建了一个自动通过数据库记录建议的搜索框，每当我搜索或输入我的搜索框重复的内容时。如何删除我的搜索框的重复？

   <script>
    $(document).ready(function(){
        $("#search_list").keyup(function(){
            $.ajax({
            type: "POST",
            url: "index.php",
            data:"keyword="+$(this).val(),
            success: function(data){

                $("#suggestion").show();
                $("#suggestion").html(data);
                $("#search_list").css("background","#FFF");
            }
            });
        });
    });
    //To select name
    function selectName(val) {
    $("#search_list").val(val);
    $("#suggestion").hide();
    }
    </script>

-------------- PHP --------------

    <?php
    foreach($result as $name) {
    ?>
    <div class="list">
     <a href="#" class="style_suggestions" onClick="selectName('<?php echo $name["n_Name"]; ?>');"><?php echo $name["n_Name"]; ?></a>
    </div>
    <?php } ?>

    <?php } } ?>

------------- HTML ------------------

<html>
  <head>
    <title>Welcome to Nava</title>
    <meta charset="utf-8">
    <meta http-equiv="X-UA-Compatible content=" ie="edge">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <link href="bootstrap.min.css" rel="stylesheet">
    <link rel="stylesheet" href="style.css" type="text/css">
    <script type="text/javascript"></script>
    <script src="jquery.min.js"></script>

  </head>
  <body>

   <div class="frmSearch">
     <input type="text" class="form-control" id="search_list" name="search_nv_box" placeholder="Name"/>
      <div id="suggestion"></div>
   </div>

Answer 1

您必须清除<div id="suggestion"></div>

每次将新数据附加到其中时

内容只需将此行添加到您的成功中：$("#suggestion").html('');

success: function(data){
                $("#suggestion").html(''); // clear your data here
                $("#suggestion").show();
                $("#suggestion").html(data);
                $("#search_list").css("background","#FFF");
            }

Answer 2

试试这个，

首先，您需要清除或清空现有建议并在此之后加载新数据。

$("#suggestion").empty();
$("#suggestion").html(data);

应该是，

$(document).ready(function(){
        $("#search_list").keyup(function(){
            $.ajax({
            type: "POST",
            url: "index.php",
            data:"keyword="+$(this).val(),
            success: function(data){
                $("#suggestion").empty();
                $("#suggestion").html(data);
                $("#suggestion").show();
                $("#search_list").css("background","#FFF");
            }
            });
        });
    });

此外，您应该只从php返回单个div元素。目前似乎每个记录都会创建一个div。

<?php
    foreach($result as $name) {
?>
    <div class="list">
     <a href="#" class="style_suggestions" onClick="selectName('<?php echo $name["n_Name"]; ?>');"><?php echo $name["n_Name"]; ?></a>
    </div>
 <?php } ?>

应该是，

<div class="list">
  <?php
    foreach($result as $name) {
  ?>
   <a href="#" class="style_suggestions" onClick="selectName('<?php echo $name["n_Name"]; ?>');"><?php echo $name["n_Name"]; ?></a>

  <?php } ?>
</div>

Answer 3

SELECT DISTINCT column_name，column_name FROM table_name;

尝试此查询以获取记录

自动建议中的搜索框重复

3 个答案: