Question

我想在我的视图中通过school_user_id过滤完成的选项。这是从这个问题开始的：RoR: Mark an object complete, save completed_on in other model

因此，学生可以完成一件作业。但在视图中，它提供了4个完整的选项，因为4个学校用户与该作业相关联。我正在尝试过滤，以便只有当前的school_user完整选项可用。

User和School_user有一对一的关系。

在我看来（这不起作用，什么也不渲染，如果删除where语句会呈现4个完整选项）

家庭作业/ show.html.erb

<% @homework.homework_students.where(school_user_id: current_user.id).each do |homework_student| %> 
 <%= link_to "complete", complete_homework_path(:homework_id => @homework, :home_work_students_id => homework_student), method: :patch %> 
<% end %>

型号：

school_user.rb

has_many :homework_students, :class_name => 'HomeworkStudent'
has_many :homeworks, :class_name => 'Homework'

homework_student.rb

has_many :homework_ratings, :class_name => 'HomeworkRating'
belongs_to :homework, :class_name => 'Homework', :foreign_key => :homework_id, dependent: :destroy
belongs_to :school_user, :class_name => 'SchoolUser', :foreign_key => :school_user_id

homework.rb

has_many :homework_students, :class_name => 'HomeworkStudent', dependent: :destroy 
belongs_to :school_user, :class_name => 'SchoolUser', :foreign_key => :school_user_id

如果我过滤其他地方，我会做这样的事情：

<% if homework.school_user.user_id == current_user.id %>

从rails控制台：

irb(main):002:0> search = HomeworkStudent.find(142) 
HomeworkStudent Load (0.5ms) SELECT `homework_students`.* FROM `homework_students` WHERE `homework_students`.`id` = 142 LIMIT 1 
=> #<HomeworkStudent id: 142, school_user_id: 10001, homework_id: 78, completed_on: "2016-11-23 18:05:34", created_at: "2016-11-22 00:27:24", updated_at: "2016-11-23 18:05:34", completed: nil>

正如您所见，school_user_id就在那里。这只是过滤掉其他用户完成的其他用户的情况。但我不知道如何用for_each做到这一点。

感谢任何帮助。谢谢。如果需要，可以提供更多代码/信息。

更新：

<% @homework.homework_students.joins(:school_user).where(school‌_user: { user_id: current_user.id }).each do |homework_student| %>

错误

Mysql2::Error: Unknown column 'school‌_user.user_id' in 'where clause': SELECT `homework_students`.* FROM `homework_students` INNER JOIN `school_users` ON `school_users`.`id` = `homework_students`.`school_user_id` WHERE `homework_students`.`homework_id` = 78 AND `school‌_user`.`user_id` = 1

Answer 1

应该是

@homework.homework_students.joins(:school_user).where(school‌_users: { user_id: current_user.id }).each

RoR：过滤for_each循环中的用户选项

1 个答案: