Question

每次我在Visual Studio 2015中运行此代码时，它都会显示错误标识符＆＃34; treasureLocation＆＃34;未定义......我做错了什么？

int main()
{
int gridSize [2];
int gridX = 0;
int gridY = 0;
int treasureLoaction[2];
int end;


std :: cout << "what size grid would you like to play on?" << std :: endl;

std :: cin >> gridSize [1];
std :: cin >> gridSize [2];

treasureLocation[1] = rand() % gridSize[1] + 1;
treasureLocation[2] = rand() % gridSize[2] + 1;

while (gridY < gridSize[2]) {
    gridY++;
    while (gridX < gridSize[1]) {
        std::cout << "* ";
        gridX++;
    } 
    std::cout << "" << std::endl;
    gridX = 0;
};

std::cout << treasureLoaction;
std::cin >> end;
return 0;

}

Answer 1

有一个错字

int treasureLoaction[2];
            ^^^^^^^^

考虑到如果一个数组有n个元素，那么索引的有效范围是[0, n-1]

这句话

std::cout << treasureLoaction;

不会像您想象的那样输出数组的元素。

您可以在循环中执行此操作，例如

for ( int x : treasureLocation ) std::cout << x << ' ';
std::cout << std::endl;

Answer 2

尝试遍历数组以打印其内容，如

for (int i = 0; i < your array length; i++) cout << array[i];

除非您尝试打印地址，并且看起来您在treasureLoaction中有拼写错误。

数组：标识符＆＃34;数组＆＃34;未定义

2 个答案: