Question

我正在处理一个项目，以便计算每个月打开和关闭的事件数量。我有一个记录所在的sql DB。我试图写一个SQL请求来计算每个月打开和关闭的事件数。

到目前为止，我能够计算下面打开的事件数量：

   SELECT
    YEAR (`startDate`),
    MONTH (`startDate`),
    COUNT(id) AS Opened
FROM
    incidents
GROUP BY
    YEAR (`startDate`),
    MONTH (`startDate`)

以下是表格的例子：

结果我需要什么。

Answer 1

从测试GROUP BY月（startdate）中选择MONTHNAME（startdate），count（MONTH（startdate）），count（MONTH（enddate））;

Answer 2

请尝试以下查询。希望它能解决你的问题。

SELECT
    MONTHNAME(start_date) as Month,
    COUNT(start_date) as CountStartDate,
    COUNT(end_date) as CountEndDate
FROM
    incidents
GROUP BY
    MONTHNAME(start_date)

Answer 3

希望这有帮助。

SELECT
    YEAR (`startDate`),
    MONTH (`endDate`),
    COUNT(id) AS Opened
FROM
    incidents
WHERE
    YEAR (`startDate`)= YEAR (`endDate`)
    MONTH (`startDate`)= MONTH (`endDate`)
GROUP BY
    YEAR (`startDate`),
    MONTH (`endDate`)

Answer 4

试试这个：

SELECT Month(startDate) as Month, COUNT(startDate) as startDate, COUNT(endDate) as countEndDate FROM incidents GROUP BY Month(startDate)

Answer 5

这也应该按照正确的顺序给你你想要的东西。希望它有所帮助

splice

Answer 6

尝试这是否有效。

CREATE TABLE abcd 
    SELECT 
        sum(if(month(start_date)=1, 1, 0)) s_1, 
        sum(if(month(start_date)=2, 1, 0)) s_2, 
        sum(if(month(start_date)=3, 1, 0)) s_3, 
        sum(if(month(start_date)=4, 1, 0)) s_4, 
        sum(if(month(start_date)=5, 1, 0)) s_5, 
        sum(if(month(start_date)=6, 1, 0)) s_6, 
        sum(if(month(start_date)=7, 1, 0)) s_7, 
        sum(if(month(start_date)=8, 1, 0)) s_8, 
        sum(if(month(start_date)=9, 1, 0)) s_9, 
        sum(if(month(start_date)=10, 1, 0)) s_10, 
        sum(if(month(start_date)=11, 1, 0)) s_11, 
        sum(if(month(start_date)=12, 1, 0)) s_12,
        sum(if(month(end_date)=1, 1, 0)) e_1, 
        sum(if(month(end_date)=2, 1, 0)) e_2, 
        sum(if(month(end_date)=3, 1, 0)) e_3, 
        sum(if(month(end_date)=4, 1, 0)) e_4, 
        sum(if(month(end_date)=5, 1, 0)) e_5, 
        sum(if(month(end_date)=6, 1, 0)) e_6, 
        sum(if(month(end_date)=7, 1, 0)) e_7, 
        sum(if(month(end_date)=8, 1, 0)) e_8, 
        sum(if(month(end_date)=9, 1, 0)) e_9, 
        sum(if(month(end_date)=10, 1, 0)) e_10, 
        sum(if(month(end_date)=11, 1, 0)) e_11, 
        sum(if(month(end_date)=12, 1, 0)) e_12  
    FROM incidents;

SELECT s_1 start, e_1 end, 'Jan' month FROM abcd 
UNION SELECT s_2 start, e_2 end, 'Feb' month FROM abcd 
UNION SELECT s_3 start, e_3 end, 'Mar' month FROM abcd
UNION SELECT s_4 start, e_4 end, 'Apr' month FROM abcd
UNION SELECT s_5 start, e_5 end, 'May' month FROM abcd
UNION SELECT s_6 start, e_6 end, 'Jun' month FROM abcd
UNION SELECT s_7 start, e_7 end, 'Jul' month FROM abcd
UNION SELECT s_8 start, e_8 end, 'Aug' month FROM abcd
UNION SELECT s_9 start, e_9 end, 'Sep' month FROM abcd
UNION SELECT s_10 start, e_10 end, 'Oct' month FROM abcd
UNION SELECT s_11 start, e_11 end, 'Nov' month FROM abcd
UNION SELECT s_12 start, e_12 end, 'Dec' month FROM abcd;

DROP TABLE abcd;

MySql - 按月计算，表中有2个不同的日期

6 个答案: